使用三个级别的自定义排序条件对对象数组进行排序

Question

我正在尝试使用三个级别的自定义排序标准对一组对象进行排序。

firstLevelSortOrder = ['10K','20K','30K','40K','50K']
secondLevelSortOrder = ['ACTIVE','CONSUMED','EXPIRED']
thirdLevelSortOrder = 
1) Oldest bountyIssueDate in case of multiple ACTIVE objects
2) Latest bountyIssueDate in case of multiple CONSUMED objects
3) Latest bountyIssueDate in case multiple EXPIRED objects

要排序的数组：

let bountyList = [
  {
    "bountyCode": "10K",
    "bountyIssueDate": "13 Jan 2020",
    "bountyStatus": "CONSUMED"
  },
  {
    "bountyCode": "20K",
    "bountyIssueDate": "13 Feb 2020",
    "bountyStatus": "CONSUMED"
  },
  {
    "bountyCode": "30K",
    "bountyIssueDate": "13 Mar 2020",
    "bountyStatus": "EXPIRED"
  },
  {
    "bountyCode": "40K",
    "bountyIssueDate": "13 Apr 2020",
    "bountyStatus": "CONSUMED"
  },
  {
    "bountyCode": "50K",
    "bountyIssueDate": "13 May 2020",
    "bountyStatus": "CONSUMED"
  },
  {
    "bountyCode": "10K",
    "bountyIssueDate": "29 May 2020",
    "bountyStatus": "ACTIVE"
  },
  {
    "bountyCode": "10K",
    "bountyIssueDate": "06 Jun 2020",
    "bountyStatus": "ACTIVE"
  },
  {
    "bountyCode": "30K",
    "bountyIssueDate": "15 Mar 2020",
    "bountyStatus": "CONSUMED"
  },
    {
    "bountyCode": "40K",
    "bountyIssueDate": "23 Apr 2020",
    "bountyStatus": "CONSUMED"
  }
]

结果数组：

[
  {
    "bountyCode": "10K",
    "bountyIssueDate": "29 May 2020",
    "bountyStatus": "ACTIVE"
  },
  {
    "bountyCode": "10K",
    "bountyIssueDate": "06 Jun 2020",
    "bountyStatus": "ACTIVE"
  },
  {
    "bountyCode": "10K",
    "bountyIssueDate": "13 Jan 2020",
    "bountyStatus": "CONSUMED"
  },
  {
    "bountyCode": "20K",
    "bountyIssueDate": "13 Feb 2020",
    "bountyStatus": "CONSUMED"
  },
  {
    "bountyCode": "30K",
    "bountyIssueDate": "15 Mar 2020",
    "bountyStatus": "CONSUMED"
  },
  {
    "bountyCode": "30K",
    "bountyIssueDate": "13 Mar 2020",
    "bountyStatus": "EXPIRED"
  },
  {
    "bountyCode": "40K",
    "bountyIssueDate": "23 Apr 2020",
    "bountyStatus": "CONSUMED"
  },
  {
    "bountyCode": "40K",
    "bountyIssueDate": "03 Apr 2020",
    "bountyStatus": "CONSUMED"
  },
  {
    "bountyCode": "50K",
    "bountyIssueDate": "13 May 2020",
    "bountyStatus": "CONSUMED"
  }
]

我已经完成了第一级排序工作，这在这个fiddle 中。试图整合二级和三级排序顺序时遇到了死胡同。还尝试将重复项分离到一个单独的数组中，对它们进行排序，然后将它们合并到一个主数组中，它变得非常混乱。

Answer 1

您需要根据按顺序检查每个排序条件来实现这一点。如果第一级排序标准给出结果，则返回该结果。否则，检查第二级。如果这给出了结果，则返回该结果。否则，返回第三级标准的结果：

var bountyList = [{
    "bountyCode": "10K",
    "bountyIssueDate": "13 Jan 2020",
    "bountyStatus": "CONSUMED"
  },
  {
    "bountyCode": "20K",
    "bountyIssueDate": "13 Feb 2020",
    "bountyStatus": "CONSUMED"
  },
  {
    "bountyCode": "30K",
    "bountyIssueDate": "13 Mar 2020",
    "bountyStatus": "EXPIRED"
  },
  {
    "bountyCode": "40K",
    "bountyIssueDate": "13 Apr 2020",
    "bountyStatus": "CONSUMED"
  },
  {
    "bountyCode": "50K",
    "bountyIssueDate": "13 May 2020",
    "bountyStatus": "CONSUMED"
  },
  {
    "bountyCode": "10K",
    "bountyIssueDate": "29 May 2020",
    "bountyStatus": "ACTIVE"
  },
  {
    "bountyCode": "10K",
    "bountyIssueDate": "06 Jun 2020",
    "bountyStatus": "ACTIVE"
  },
  {
    "bountyCode": "30K",
    "bountyIssueDate": "15 Mar 2020",
    "bountyStatus": "CONSUMED"
  },
  {
    "bountyCode": "40K",
    "bountyIssueDate": "23 Apr 2020",
    "bountyStatus": "CONSUMED"
  }
]

var firstLevelSortOrder = ['10K', '20K', '30K', '40K', '50K']
var secondLevelSortOrder = ['ACTIVE', 'CONSUMED', 'EXPIRED']

console.log(bountyList.sort(
  function(a, b) {
    var first = firstLevelSortOrder.indexOf(a.bountyCode) - firstLevelSortOrder.indexOf(b.bountyCode);
    if (first != 0) {
      return first;
    }
    // first order equal, test second order
    var second = secondLevelSortOrder.indexOf(a.bountyStatus) - secondLevelSortOrder.indexOf(b.bountyStatus);
    if (second != 0) {
      return second;
    }
    // second order also equal, test dates dependent on bountyStatus
    if (a.bountyStatus == 'ACTIVE') {
      // want earliest date sorted first
      return Date.parse(a.bountyIssueDate) - Date.parse(b.bountyIssueDate);
    } 
    else {
      // want latest date sorted first for CONSUMED or EXPIRED
      return Date.parse(b.bountyIssueDate) - Date.parse(a.bountyIssueDate);
    }
  }
))

请注意，为了方便演示我用来Date.parse()解析对象中日期的代码。通常，由于浏览器不一致（请参阅手册），因此不建议这样做，为此您应该手动将日期解析为时间戳。