带有后退按钮的Android Webview,如果是的话

Question

漠视.我正在打开安装的错误应用程序.它运作得很好.:)

我的后退按钮在我的webview中正常工作,但我想知道一些事情.如何使webview返回,直到它不能再出现,而不是退出程序,让它打开一个对话框,询问用户是否确定他们不会退出.这是我对代码的看法.
感谢您抽出宝贵的时间.

.java文件

package com.vtd.whatthe;

import android.app.Activity;
import android.app.AlertDialog;
import android.app.AlertDialog.Builder;
import android.app.Dialog;
import android.content.DialogInterface;
import android.os.Bundle;
import android.view.KeyEvent;
import android.view.View;
import android.widget.Toast;
import android.webkit.WebView;
import android.webkit.WebViewClient;

public class WhatThe extends Activity {
    private WebView webview;

    /** Called when the activity is first created. */

    public void onBackPressed (){

        if (webview.isFocused() && webview.canGoBack()) {
                webview.goBack();       
        }
        else {
                openMyDialog(null);

        }
    }

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        webview = (WebView) findViewById(R.id.webview);
        webview.setWebViewClient(new HelloWebViewClient());
        webview.getSettings().setJavaScriptEnabled(true);
        webview.setInitialScale(50); 
        webview.getSettings().setUseWideViewPort(true); 
        webview.loadUrl("http://test2.com/");
    }
    private class HelloWebViewClient extends WebViewClient {

        public boolean shouldOverrideUrlLoading(WebView view, String url) {
            view.loadUrl(url);
            return true;
        }

            }

    public void openMyDialog(View view) {
        showDialog(10);
    }

    @Override
    protected Dialog onCreateDialog(int id) {
        switch (id) {
        case 10:
            // Create our AlertDialog
            Builder builder = new AlertDialog.Builder(this);
            builder.setMessage("Are you sure you want to exit? You have unlimited guesses!")
                    .setCancelable(true)
                    .setPositiveButton("Yes",
                            new DialogInterface.OnClickListener() {
                                @Override
                                public void onClick(DialogInterface dialog,
                                        int which) {
                                    // Ends the activity
                                    WhatThe.this.finish();
                                }
                            })
                    .setNegativeButton("Keep Guessing!",
                            new DialogInterface.OnClickListener() {

                                @Override
                                public void onClick(DialogInterface dialog,
                                        int which) {
                                    Toast.makeText(getApplicationContext(),
                                            "Good Luck!",
                                            Toast.LENGTH_SHORT).show();
                                }
                            });

            return builder.create();


        }
        return super.onCreateDialog(id);
    }
}

Answer 1

以下代码对我有用

public void onBackPressed (){

    if (webview.isFocused() && webview.canGoBack()) {
            webview.goBack();       
    }
    else {
            super.onBackPressed();
            finish();
    }
}

Answer 2

尝试下面的代码片段

public void back() {
    if (history.size() > 0) {
        history.remove(history.size() - 1);
        if (history.size() <= 0) {
            finish();
        } else {
            setContentView(history.get(history.size() - 1));
        }
    } else {
        finish();
    }
}

@Override
public void onBackPressed() {
    TopNewsGroup.group.back();
}

@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
    if (keyCode == KeyEvent.KEYCODE_BACK) {
        TopNewsGroup.group.back();
        return true;
    }
    return super.onKeyDown(keyCode, event);
}