Ikr*_*kra 3 mysql query-builder laravel eloquent laravel-6
如何在查询构建器中表达此代码。我正在使用 Laravel 6。
SELECT * FROM feedback GROUP BY noTicket having count(`status`) < 2
Run Code Online (Sandbox Code Playgroud)
我的代码:
$feedback = DB::table('feedback')
->groupBy('noTicket')
->having('count(status)', '<', 2)
->get();
Run Code Online (Sandbox Code Playgroud)
错误代码:
SQLSTATE[42000]: Syntax error or access violation: 1055 'sifora.feedback.idFeedback' isn't in GROUP BY
(SQL: select * from `feedback` group by `noTicket` having `count(status)` < 2)
Run Code Online (Sandbox Code Playgroud)
我的代码有什么问题?sql 代码与查询构建器之间似乎匹配。
谢谢
这是查询的工作版本
select noTicket
from feedback
group by noTicket
having count(status) < 2;
Run Code Online (Sandbox Code Playgroud)
这是查询构建器;
return DB::table('feedback')
->groupBy('noTicket')
->having(DB::raw('count(status)'), '<', 2)
->pluck('noTicket'); // you may replace this with get()/select()
Run Code Online (Sandbox Code Playgroud)
归档时间: |
|
查看次数: |
6589 次 |
最近记录: |