为什么MooseX :: Storage似乎不遵循某些对象的属性特征？

Question

我已经整理了一个小测试用例来演示我的问题:

package P1;
use Moose;
use MooseX::Storage;
with Storage;

has 'blah' => (
    is => 'rw',
);

package P2;
use Moose;
use MooseX::Storage;
with Storage;

has 'lol' => (
    is => 'rw',
    traits => ['DoNotSerialize']
);

package P3;
use Moose;
extends 'P2';

has 'magic' => (
    is => 'rw',
);

package Test;
my $obj = P3->new(
    magic => 'This ok!',
    lol   => sub { 'weee' }
);

my $stored = P1->new(blah => $obj);

use Data::Dumper; print Dumper ($stored->pack);

我希望这打印对象,但不打包P2包中的'lol'属性 - 但是,我仍然可以在结果中看到这个 $stored->pack

$VAR1 = {
          '__CLASS__' => 'P1',
          'blah' => bless( {
                             'magic' => 'This ok!',
                             'lol' => sub { "DUMMY" }
                           }, 'P3' )
        };

我使用MooseX :: Storage是错误的,还是看起来像有错误的行为？

Answer 1

看起来像个臭虫的Yup.你能把它变成一个使用Test :: More并将它提交到RT队列的测试,有人(可能是我)会修复它.

请注意,如果您转储$ obj-> store,您会看到该特征已正确应用于direct属性,但它似乎在继承过程中丢失了.

您可以在RT中报告针对MooseX :: Storage的错误

Answer 2

你可以把“blah”作为 P3 的 isa....

has 'blah' => (
    is  => 'rw',
    isa => 'P3',
);

现在 Dumper( $stored->pack ) 显示了这个......

$VAR1 = {
      '__CLASS__' => 'P1',
      'blah' => {
                  '__CLASS__' => 'P3',
                  'magic' => 'This ok!'
                }
};

这看起来像是这个 Moose 对象的正确序列化？