如何在 PowerShell 中将字符串转换为双精度？

Question

我在 PowerShell 中有一个脚本，用于从 CSV 导入数据。我收到错误

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无法将值“日记帐金额”转换为类型“System.Double”。错误：“输入字符串的格式不正确。” 在 C:\TestPowerShell\TestPowerShell1.ps1:98 char:1 + $JournalAmount = [double] $_.PSObject.Properties['Journal Amount'].Va ... + ~~~~~~~~~~~~ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~~~ + CategoryInfo：InvalidArgument：(:) []，RuntimeException + ExcellentQualifiedErrorId：InvalidCastFromStringToDoubleOrSingle

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这是我的代码：

Get-Content "config.txt" | foreach-object -begin {$h=@{}} -process { $k = [regex]::split($_,'='); if(($k[0].CompareTo("") -ne 0) -and ($k[0].StartsWith("[") -ne $True)) { $h.Add($k[0], $k[1]) } }

$FileBrowserInitialDir = $h.FileBrowserInitialDir
$Header = 'Terminal','Company','Journal Account Code','Project','Task','Line of Business','Date','Journal Amount','Report Entry Vendor Description'

$TIDataFilePath = $h.TIDataFilePath
$TIDataFileBaseName = $h.TIDataFileBaseName

$TIScreenID = $h.TIScreenID
$TIControlFile = $h.TIControlFile
$TIErrLog = $h.TIErrLog

$ResultsFilePath = $h.ResultsFilePath
$ResultsFileBaseName = $h.ResultsFileBaseName

$dt = Get-Date -Format "MMddyyyyHHmmss"
$TIDataFile = "$($TIDataFileBaseName)$($dt).txt"
$ResultsFile = "$($ResultsFileBaseName)$($dt).txt"

Add-Type -AssemblyName System.Windows.Forms
$FileBrowser = New-Object System.Windows.Forms.OpenFileDialog -Property @{ 
    InitialDirectory = $FileBrowserInitialDir
    Filter = 'CSV (*.csv)|*.csv'
    Title = "Select Expense csv file"
}
$null = $FileBrowser.ShowDialog()

if($FileBrowser.FileName -eq ""){
    exit
}


 $EXPENSECSV = Import-CSV $FileBrowser.FileName -Header $Header
 New-Item -path $TIDataFilePath -name $TIDataFile -type "file"
 $EXPENSECSV |foreach-object{    

$Terminal =  $_.PSObject.Properties['Terminal'].Value
$Terminal = $Terminal.Insert(0,'0')

$CompanyTemp =  $_.PSObject.Properties['Company'].Value
$CompanyTemp = $CompanyTemp.Insert(0,'0')
#$Company= [String]::Concat($_.Terminal,$CompanyTemp) 
$Company= [String]::Concat($Terminal,$CompanyTemp) 
$LineofB =  $_.PSObject.Properties['Line of Business'].Value
#$JournalAmount = [double] $_.PSObject.Properties["Journal Amount"].Value
 $LineofB = $LineofB.Insert(0,'0')

 $Account = $_.PSObject.Properties['Journal Account Code'].Value
$Sub = $LineofB

$TranDateStr =  $_.PSObject.Properties['Date'].Value
$JournalAmount = [double] $_.PSObject.Properties['Journal Amount'].Value
$Description =  $_.PSObject.Properties['Report Entry Vendor Description'].Value

    $row = ""
    $row +=  "`"Level1`","
    $row +=  "`"$($Company)`","
    $row +=  "`"$($Account)`","
    $row +=  "`"$($Sub)`","
    $row +=  "`"$($TranDateStr)`","


    # Convert Concur Amount to Credit/Debit Amount
    # Postive Amount  --> Debit Amount
    # Negative Amount --> Credit Amount
    if($JournalAmount -lt 0){
        $JournalAmount*= -1
        $row += "`"$($JournalAmount)`","   #Credit Amount
        $row += "`"`","             #Debit Amount
    }
    else {
        $row += "`"`","             #Credit Amount
        $row += "`"$($JournalAmount)`","   #Debit Amount
    }

    $row += "`"$($Description)`""

   Add-Content -Path "$($TIDataFilePath)$($TIDataFile)" -Value $row
 }

 #Results
 New-Item -path $ResultsFilePath -name $ResultsFile -type "file"

 $ResultsStr =   "----------------------------------------------------------------------------------`n"
$ResultsStr +=  "                             Concur to Dynamics SL                                   `n"
$ResultsStr +=  "----------------------------------------------------------------------------------`n"
$ResultsStr +=  "Copy and paste the following into the Transaction Import screen.`n"
$ResultsStr += "Line 1: Data File Name`n"
$ResultsStr += "Line 2: Screen ID`n"
$ResultsStr += "Line 3: Control File Name`n"
$ResultsStr += "Line 4: Output Log File`n`n`n"
$ResultsStr += "$($TIDataFilePath)$($TIDataFile)`n"
$ResultsStr += "$($TIScreenID)`n"
$ResultsStr += "$($TIControlFile)`n"
$ResultsStr += "$($TIErrLog)"


 Add-Content -path "$($ResultsFilePath)$($ResultsFile)" -value $ResultsStr

Start-Process "$($ResultsFilePath)$($ResultsFile)"

Answer 1

回答所提出的问题：

• 将字符串转换为[double]- 正如您自己尝试过的那样 -确实有效，但前提是该字符串被识别为（浮点）数字。

  • 警告：由于PowerShell 的强制转换是区域性不变的，因此仅.被识别为小数点，并且,始终被解释为千位分组分隔符。

  • 要以文化敏感的方式进行解析，请使用[double]::Parse($string)基于当前文化的规则进行解析（如 中所反映的$PSCulture）；传递一个实例作为第二个参数，以根据给定[cultureinfo]文化的规则进行解析（例如，要根据法国文化的规则进行解析，请使用）[double]::Parse($string, [cultureinfo] 'fr-FR')

• 如果无法识别字符串值，您可以使用以下方法之一来处理这种情况：

  • 使用try/catch来处理错误；例如，悄悄地默认为0：

    • [double] $double = try { $string } catch { 0 }

  • 使用-as条件类型转换运算符，它返回指定类型的实例，或者如果转换失败，则$null：

    • $double = $string -as [double]; if ($null -eq $double) { ... }

至于你尝试过的：

正如Mathias R. Jessen指出的那样，问题的可能原因是您的 CSV 文件本身具有标题行，但您还通过参数提供了标题-Header。

这会导致 CSV 文件的标题行被误读为第一个数据行，因此返回的第一个对象将列（标题）名称Import-Csv包含为属性值 - 这会导致转换失败，因为您正在有效地执行以下操作：[double]
[double] 'Journal Amount'

所以：

• 省略-Header调用中的参数Import-Csv。

• 作为优化，通过使用普通的点表示法简化属性值检索；只需使用引号来指定属性名称Journal Amount，因为它包含空格：

Import-CSV $FileBrowser.FileName | # !! No -Header argument
  ForEach-Object {
    # Simpler and more efficient than:
    #   $JournalAmount = [double] $_.PSObject.Properties['Journal Amount'].Value
    $JournalAmount = [double] $_.'Journal Amount'
  }
# ...

Answer 2

这解决了这个问题：

$JournalAmount = $JournalAmount -as [double]
$JournalAmount = $_.PSObject.Properties['Journal Amount'].Value