Flutter 测试通过子文本查找

Question

如果找到特定文本作为完整字符串匹配或作为其他文本的子字符串，是否可以断言测试？

只要在Foo任何地方找到字符串，即使作为其他字符串的子字符串，我希望以下测试通过。我应该改变什么？

import 'package:flutter/material.dart';
import 'package:flutter_test/flutter_test.dart';
void main() {
  testWidgets('Find sub text', (WidgetTester tester) async {
    await tester.pumpWidget(Text('Error code is Foo', textDirection: TextDirection.ltr));
    expect(find.text('Error code is Foo'), findsOneWidget);
    expect(find.text('Foo'), findsOneWidget);
  });
}

迄今为止：

The following TestFailure object was thrown running a test:
  Expected: exactly one matching node in the widget tree
  Actual: _TextFinder:<zero widgets with text "Foo" (ignoring offstage widgets)>
   Which: means none were found but one was expected

Answer 1

您可以使用find.textContaining：

import 'package:flutter/material.dart';
import 'package:flutter_test/flutter_test.dart';
void main() {
  testWidgets('Find sub text', (WidgetTester tester) async {
    await tester.pumpWidget(Text('Error code is Foo', textDirection: TextDirection.ltr));
    expect(find.text('Error code is Foo'), findsOneWidget);
    expect(find.textContaining('Foo'), findsOneWidget);
  });
}

Answer 2

代替：

expect(find.text('Foo'), findsOneWidget);

和：

expect(find.byWidgetPredicate((widget) {
  if (widget is Text) {
    final Text textWidget = widget;
    if (textWidget.data != null) return textWidget.data.contains('Foo');
    return textWidget.textSpan.toPlainText().contains('Foo');
  }
  return false;
}), findsOneWidget);

您将首先找到文本小部件，然后检查文本字符串中的子字符串