我有以下地图列表,
[
{
"FullName":"Harry Potter",
"DateOfBirth": "2020/02/16",
"Department":"Branch Operation",
"BirthDay":"Friday"
},
{
"FullName":"John Wick",
"DateOfBirth": "2020/02/16",
"Department":"Finance",
"BirthDay":"Friday"
},
{
"FullName":"Solomon Kane",
"DateOfBirth":2020/02/19,
"Department":"Loan",
"BirthDay":"Monday"
}
]
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我想操作上面的数据,以便数据按它们的 分组DateOfBirth,这样结果就会看起来像这样。
[
{
"DateOfBirth": "2020/02/16",
"BirthDay": "Friday",
"Data":[
{
"FullName": "Harry Potter",
"Department":"Branch Operation",
},
{
"FullName":"John Wick",
"Department":"Finance",
}
]
},
{
"DateOfBirth": "2020/02/19",
"BirthDay": "Monday",
"Data":[
{
"FullName":"Solomon Kane",
"Department":"Loan"
}
]
},
]
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在Javascript中,这可以通过使用reduce函数然后使用对象键映射来实现。我也知道 dart 有一个有用的包叫做 collection
由于我是飞镖和扑的新手,我不知道该怎么做。有人可以帮我吗?
谢谢
gug*_*gge 10
你可以使用fold并做这样的事情
const data = [...];
void main() {
final value = data.fold(Map<String, List<dynamic>>(), (Map<String, List<dynamic>> a, b) {
a.putIfAbsent(b['DateOfBirth'], () => []).add(b);
return a;
}).values
.where((l) => l.isNotEmpty)
.map((l) => {
'DateOfBirth': l.first['DateOfBirth'],
'BirthDay': l.first['BirthDay'],
'Data': l.map((e) => {
'Department': e['Department'],
'FullName': e['FullName'],
}).toList()
}).toList();
}
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或者像这样,如果你想使用扩展运算符,我不知道它是否非常可读。
final result = data.fold({}, (a, b) => {
...a,
b['DateOfBirth']: [b, ...?a[b['DateOfBirth']]],
}).values
.where((l) => l.isNotEmpty)
.map((l) => {
'DateOfBirth': l.first['DateOfBirth'],
'BirthDay': l.first['BirthDay'],
'Data': l.map((e) => {
'Department': e['Department'],
'FullName': e['FullName'],
}).toList()
}).toList();
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