你能在SASS/SCSS CSS中使用多个条件吗?

Pet*_*ton 13 html css ruby sass

我正在使用SCSS代码来设置我的ruby应用程序的样式,并且我正在尝试编写自己的"圆形"mixin以帮助进行多浏览器边框舍入.

目前我有以下内容:

@mixin rounded($corner: all , $radius: 8px) {
  @if $corner==all || $corner==bottom || $corner == right || $corner==bottom-right{webkit-border-bottom-right-radius: $radius;}
  @if $corner==all || $corner==bottom || $corner == left || $corner==bottom-left{-webkit-border-bottom-left-radius: $radius;}
  @if $corner==all || $corner==top || $corner == right || $corner==top-right{-webkit-border-top-right-radius: $radius;}
  @if $corner==all || $corner==bottom || $corner == left || $corner==top-left{-webkit-border-top-left-radius: $radius;}

  @if $corner==all || $corner==bottom || $corner == right || $corner==bottom-right{-khtml-border-radius-bottomright: $radius;}
  @if $corner==all || $corner==bottom || $corner == left || $corner==bottom-left{-khtml-border-radius-bottomleft: $radius;}
  @if $corner==all || $corner==top || $corner == right || $corner==top-right{-khtml-border-radius-topright: $radius;}
  @if $corner==all || $corner==bottom || $corner == left || $corner==top-left{-khtml-border-radius-topleft: $radius;}

  @if $corner==all || $corner==bottom || $corner == right || $corner==bottom-right{-moz-border-radius-bottomright: $radius;}
  @if $corner==all || $corner==bottom || $corner == left || $corner==bottom-left{-moz-border-radius-bottomleft: $radius;}
  @if $corner==all || $corner==top || $corner == right || $corner==top-right{-moz-border-radius-topright: $radius;}
  @if $corner==all || $corner==bottom || $corner == left || $corner==top-left{-moz-border-radius-topleft: $radius;}

  @if $corner==all || $corner==bottom || $corner == right || $corner==bottom-right{border-bottom-right-radius: $radius;}
  @if $corner==all || $corner==bottom || $corner == left || $corner==bottom-left{border-bottom-left-radius: $radius;}
  @if $corner==all || $corner==top || $corner == right || $corner==top-right{border-top-right-radius: $radius;}
  @if $corner==all || $corner==bottom || $corner == left || $corner==top-left{border-top-left-radius: $radius;}
}
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但是,似乎SASS只能在if语句中处理一个条件?有没有办法解决这个问题,还是我必须为每个圆角做四个if语句?

Bob*_*ler 34

您需要使用'或'而不是'||'.请参阅Sass文档.此外,看起来你在每个块的最后一个@if语句中都有一个拼写错误:$ corner == bottom应该是$ corner == top