如何在Python中实现curl -u？

Question

我正在尝试使用http://developer.github.com/v3/来检索项目问题.这有效:

curl -u "Littlemaple:mypassword" https://api.github.com/repos/MyClient/project/issues

它返回我客户项目的所有私人问题.但是,我无法找到如何在Python中实现它.我找到的两种方式(例如Python urllib2 Basic Auth Problem)都不起作用,它们返回404或403错误:

def fetch(url, username, password):
    """Wonderful method found on forums which does not work.""""
    passman = urllib2.HTTPPasswordMgrWithDefaultRealm()
    passman.add_password(None, url, username, password)
    urllib2.install_opener(urllib2.build_opener(urllib2.HTTPBasicAuthHandler(passman)))

    req = urllib2.Request(url)
    f = urllib2.urlopen(req)
    return f.read()

...和:

def fetch(url, username, password):
    """Wonderful method found on forums which does not work neither.""""
    request = urllib2.Request(url)
    base64string = base64.encodestring('%s:%s' % (username, password)).replace('\n', '')
    request.add_header("Authorization", "Basic %s" % base64string)   
    return urllib2.urlopen(request).read()

有任何想法吗？提前致谢!

Answer 1

r = requests.get('https://api.github.com', auth=('user', 'pass'))

Python请求是这里的方式.我一直在工作和家里广泛使用请求进行各种Web服务交互.与之前相比,使用起来很愉快.注意:auth关键字arg适用于任何需要auth的调用.因此,您可以谨慎使用它,即.每次对github的调用都不需要它,只需要登录.例如:

r = request.get('https://api.github.com/gists/starred, auth=('user', 'pass'))

这里记录了github登录:

http://pypi.python.org/pypi/requests/0.6.1

Answer 2

如果它是404,你可能只是错误的URL.如果它是403,也许你的领域错了.

对于初学者,您将URL传递给add_password,而实际上您应该只传递基本URL.而且,您应该只创建一个新的开启器,而不是install_opener.

请参阅此配方以获取示例:

class NoOpHandler(urllib2.HTTPRedirectHandler):
    def redirect_request(self, req, fp, code, msg, headers, newUrl):
        return None

passmanager = urllib2.HTTPPasswordMgrWithDefaultRealm()
passmanager.add_password(None, baseurl, username, password)
auth_handler = urllib2.HTTPBasicAuthHandler(passmanager)
opener = urllib2.build_opener(auth_handler, NoOpHandler())