JPA 原生 sql 查询中的 like 子句

Question

我有一个返回产品列表的查询：

@Query(value = "Select * from Product join Product_Pro pp on Product.ID = pp.PRODUCT_ID where A_ID= ?1 order by name",
        nativeQuery = true)
    List<Product> findAll(long id);

我如何LIKE为此添加一个子句？

当我在数据库中执行此语句时，得到结果：

Select * from Product join Product_Pro pp on Product.ID = pp.PRODUCT_ID where A_ID= ?1 AND name LIKE '%someString%' AND content LIKE '%someString%' order by name

但如何添加LIKE到我的 JPA 本机查询中？

我努力了：

@Query(value = "Select * from Product join Product_Pro pp on Product.ID = pp.PRODUCT_ID where A_ID= ?1 and name LIKE '%?%' order by name",
            nativeQuery = true)
        List<Product> findAll(long id, String name);

和

@Query(value = "Select * from Product join Product_Pro pp on Product.ID = pp.PRODUCT_ID where A_ID= ?1 and name LIKE '%:name%' order by name",
            nativeQuery = true)
        List<Product> findAll(long id,@Param("name") String name);

但这些都不起作用。

Answer 1

我认为你想要CONCAT()：

and name LIKE CONCAT('%', ?2, '%')