Spa*_*fa9 4 javascript asp.net jquery content-pages
如何从asp.net按钮单击事件中调用showDialog.我的页面是一个内容页面,其中包含与之关联的母版页.
我尝试了以下内容
<asp:Button ID="ButtonAdd" runat="server" Text="Add"
OnClientClick="showDialog('#addPerson');" />
<asp:Button ID="ButtonAdd" runat="server" Text="Add"
OnClientClick="showDialog(#<%=addPerson.ClientID %>);" />
Run Code Online (Sandbox Code Playgroud)
我还必须从gridview模板按钮调用此相同的函数来修改对话框中的记录.
<script type="text/javascript">
// Used the following example to open the dialog withJquery
var dl;
$(document).ready(function () {
//Adding the event of opening the dialog from the asp.net add button.
//setup edit person dialog
$('#addPerson').dialog({
//Setting up the dialog properties.
show: "blind",
hide: "fold",
resizable: false,
modal: true,
height: 400,
width: 700,
title: "Add New Member",
open: function (type, data) {
$(this).parent().appendTo("form:first");
}
});
//setup edit person dialog
$('#editPerson').dialog({
//Setting up the dialog properties.
show: "blind",
hide: "fold",
resizable: false,
modal: true,
height: 400,
width: 700,
title: "Modify Member",
open: function (type, data) {
$(this).parent().appendTo("form");
}
});
function showDialog(id) {
$('#' + id).dialog("open");
}
// function closeDialog(id) {
// $('#' + id).dialog("close");
// }
//Adding a event handler for the close button that will close the dialog
$("a[id*=ButtonCloseDlg]").click(function (e) {
$("#divDlg").dialog("close");
return false;
});
});
</script>
Run Code Online (Sandbox Code Playgroud)
试图从gridview编辑按钮调用jquery对话框并获得相同的错误对象不支持此属性或方法?
<input type="submit" name="ctl00$ContentPlaceHolder1$GridViewMembers$ctl02$Button1" value="Edit" onclick="showDialog('addPerson');" id="ContentPlaceHolder1_GridViewMembers_Button1_0" />
Run Code Online (Sandbox Code Playgroud)
如果您在按此按钮时不需要发回帖子,则无需进行服务器控件的开销.
<input id="addButton" type="button" value="Add" />
<script type="text/javascript" language="javascript">
$(document).ready(function()
{
$('#addButton').click(function()
{
showDialog('#addPerson');
});
});
</script>
Run Code Online (Sandbox Code Playgroud)
如果您仍然需要能够回发,您可以使用一些不同的代码有条件地停止其余的按钮操作:
<asp:Button ID="buttonAdd" runat="server" Text="Add" />
<script type="text/javascript" language="javascript">
$(document).ready(function()
{
$('#<%= buttonAdd.ClientID %>').click(function(e)
{
showDialog('#addPerson');
if(/*Some Condition Is Not Met*/)
return false;
});
});
</script>
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
101141 次 |
| 最近记录: |