Art*_*ezy 2 python dataframe python-3.x pandas
我有一个数据框如下
Name Age
0 Tom 20
1 nick 21
2
3 krish 19
4 jack 18
5
6 jill 26
7 nick
Run Code Online (Sandbox Code Playgroud)
期望的输出是
Name Age
0 Tom 20
1 nick 21
3 krish 19
4 jack 18
6 jill 26
7 nick
Run Code Online (Sandbox Code Playgroud)
索引不应更改,如果可能的话,如果我不必将空字符串转换为 NaN,那就太好了。仅当所有列都有''空字符串时才应将其删除
你可以做:
# df.eq('') compare every cell of `df` to `''`
# .all(1) or .all(axis=1) checks if all cells on rows are True
# ~ is negate operator.
mask = ~df.eq('').all(1)
# equivalently, `ne` for `not equal`,
# mask = df.ne('').any(axis=1)
# mask is a boolean series of same length with `df`
# this is called boolean indexing, similar to numpy's
# which chooses only rows corresponding to `True`
df = df[mask]
Run Code Online (Sandbox Code Playgroud)
或者在一行中:
df = df[~df.eq('').all(1)]
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
5762 次 |
| 最近记录: |