是否有postgresql函数将返回一个舍入到最近分钟的时间戳?输入值是时间戳,返回值应该是时间戳.
Boh*_*ian 105
使用内置函数date_trunc(text, timestamp)
,例如:
select date_trunc('minute', now())
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编辑:这截断到最近一分钟.要获得舍入结果,请先为时间戳添加30秒,例如:
select date_trunc('minute', now() + interval '30 second')
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这将返回最近的分钟.
有关详细信息,请参阅Postgres日期/时间函数和运算符
Pet*_*uss 13
回答类似(更通用)的问题,
"......到最近的分钟间隔 "(1分钟,5分钟,10分钟等)
CREATE FUNCTION round_minutes(TIMESTAMP WITHOUT TIME ZONE, integer)
RETURNS TIMESTAMP WITHOUT TIME ZONE AS $$
SELECT
date_trunc('hour', $1)
+ cast(($2::varchar||' min') as interval)
* round(
(date_part('minute',$1)::float + date_part('second',$1)/ 60.)::float
/ $2::float
)
$$ LANGUAGE SQL IMMUTABLE;
CREATE FUNCTION round_minutes(TIMESTAMP WITHOUT TIME ZONE, integer,text)
RETURNS text AS $$
SELECT to_char(round_minutes($1,$2),$3)
$$ LANGUAGE SQL IMMUTABLE;
SELECT round_minutes('2010-09-17 16:23:12', 5);
-- 2010-09-17 16:25:00
SELECT round_minutes('2010-09-17 16:23:12', 10, 'HH24:MI');
-- 16:20
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改编自http://wiki.postgresql.org/wiki/Round_time,并改编 为@CrowMagnumb显示的"精确回合".
在尝试使用上述彼得的答案来创建天花板和地板函数时,我发现调用舍入函数时也必须考虑秒数。这是我将要进行舍入,舍入和上限时间戳记的函数集。
CREATE OR REPLACE FUNCTION round_minutes( TIMESTAMP WITHOUT TIME ZONE, integer)
RETURNS TIMESTAMP WITHOUT TIME ZONE AS $$
SELECT date_trunc('hour', $1) + (cast(($2::varchar||' min') as interval) * round( (date_part('minute',$1)::float + date_part('second',$1)/ 60.)::float / cast($2 as float)))
$$ LANGUAGE SQL IMMUTABLE STRICT;
CREATE OR REPLACE FUNCTION floor_minutes( TIMESTAMP WITHOUT TIME ZONE, integer )
RETURNS TIMESTAMP WITHOUT TIME ZONE AS $$
SELECT round_minutes( $1 - cast((($2/2)::varchar ||' min') as interval ), $2 );
$$ LANGUAGE SQL IMMUTABLE STRICT;
CREATE OR REPLACE FUNCTION ceiling_minutes( TIMESTAMP WITHOUT TIME ZONE, integer )
RETURNS TIMESTAMP WITHOUT TIME ZONE AS $$
SELECT round_minutes( $1 + cast((($2/2)::varchar ||' min') as interval ), $2 );
$$ LANGUAGE SQL IMMUTABLE STRICT;
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向下舍入时间戳
CREATE or replace FUNCTION date_round_down(base_date timestamptz, round_interval INTERVAL)
RETURNS timestamptz AS $BODY$
SELECT TO_TIMESTAMP(EXTRACT(epoch FROM date_trunc('hour', $1))::INTEGER + trunc((EXTRACT(epoch FROM $1)::INTEGER - EXTRACT(epoch FROM date_trunc('hour', $1))::INTEGER) / EXTRACT(epoch FROM $2)::INTEGER) * EXTRACT(epoch FROM $2)::INTEGER)
$BODY$ LANGUAGE SQL STABLE;
SELECT date_round_down('2017-06-02 16:39:35', '15 minutes') -- 2017-06-02 16:30:35
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