根据字段的开头选择记录？

Question

我有一个数据库,其表具有标识符c1,c2,c3..etc ..

不是编写一堆包含ORs 的查询,而是如何修改下面的查询,以便捕获以某个字母开头的所有记录？

SELECT 
    Person.spineinjuryAdmit, 
    tblComorbidity.comorbidityexplanation,
    Count(tblComorbidity.comorbidityexplanation) AS CountOfcomorbidityexplanation

FROM tblKentuckyCounties 
INNER JOIN (tblComorbidity 
            INNER JOIN (Person 
                        INNER JOIN tblComorbidityPerson 
                            ON Person.PersonID = tblComorbidityPerson.personID) 
                ON tblComorbidity.ID = tblComorbidityPerson.comorbidityFK) 
    ON tblKentuckyCounties.ID = Person.County
GROUP BY    Person.spineinjuryAdmit, 
            tblComorbidity.comorbidityexplanation
HAVING (((Person.spineinjuryAdmit)="c1" Or 
         (Person.spineinjuryAdmit)="c2" Or 
         (Person.spineinjuryAdmit)="c3"));

Answer 1

你试过用过LIKE吗？举个例子:

SELECT * FROM patients WHERE lastName LIKE 'm%';

这将返回patients.lastName以'm'开头的记录.'%'字符可能是'*'用于访问,我不记得了.在某些数据库中,您还可以使用"_"来匹配单个字符(或者您添加的许多下划线).

Answer 2

    SELECT Person.spineinjuryAdmit, tblComorbidity.comorbidityexplanation, Count(tblComorbidity.comorbidityexplanation) AS CountOfcomorbidityexplanation
FROM tblKentuckyCounties INNER JOIN (tblComorbidity INNER JOIN (Person INNER JOIN tblComorbidityPerson ON Person.PersonID = tblComorbidityPerson.personID) ON tblComorbidity.ID = tblComorbidityPerson.comorbidityFK) ON tblKentuckyCounties.ID = Person.County
GROUP BY Person.spineinjuryAdmit, tblComorbidity.comorbidityexplanation
HAVING (Person.spineinjuryAdmit LIKE "c*");