nspredicate数组中的多个项目

suj*_*406 5 iphone core-data nspredicate

如何使用NSPredicate来满足多种条件

NSEntityDescription *entity = [NSEntityDescription entityForName:@"MessageData" inManagedObjectContext:managedObjectContext];
    NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init];
    [fetchRequest setEntity:entity];
    NSPredicate *predicate = [NSPredicate predicateWithFormat:@"msg_id = %@",msg_id];

    [fetchRequest setPredicate:predicate];
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我需要获取其中msg_id =数组中的值的对象

Dee*_*olu 13

你可以做到"msg_id IN %@", array.