hkB*_*sai 1 php arrays constructor global class
我的目标是从另一个PHP文件中定义的全局数组中检索一些数据.我的代码在"database.php"文件中运行,我想要使用的数组在"config.php"文件中.
我的代码如下:
config.php文件
$CONFIG = array();
// ...
$CONFIG["DATABASE"] = array();
$CONFIG["DATABASE"]["USERNAME"] = "user";
$CONFIG["DATABASE"]["PASSWORD"] = "pass";
$CONFIG["DATABASE"]["HOSTNAME"] = "127.0.0.1";
$CONFIG["DATABASE"]["DATABASE"] = "my_db";
// ...
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为database.php
require('config.php');
class Database
{
protected $m_Link;
private $m_User;
private $m_Pass;
private $m_Host;
private $m_Data;
private $m_bConnected;
public function __construct()
{
global $CONFIG;
$this->m_User = $CONFIG["DATABASE"}["USERNAME"]; // Line #16
$this->m_Pass = $CONFIG["DATABASE"}["PASSWORD"];
$this->m_Host = $CONFIG["DATABASE"}["HOSTNAME"];
$this->m_Data = $CONFIG["DATABASE"}["DATABASE"];
$this->m_bConnected = false;
$this->Connect();
}
// ...
};
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给出的错误是:
解析错误:语法错误,意外'}',期待']'在第16行的C:...\database.php中
我无法弄清楚我在这里做错了什么.
请帮我修复此错误.
(注意:PHP版本是5.3.0)
您没有正确配对括号
$this->m_User = $CONFIG["DATABASE"}["USERNAME"];
----------------------------------^
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应该
$this->m_User = $CONFIG["DATABASE"]["USERNAME"];
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