根据 Pandas DataFrame 中的值序列生成索引元组

Meh*_*are 2 python dataframe python-3.x pandas

这是我上一个问题的后续:根据 Pandas DataFrame 列中的值序列查找行的索引

我想得到一个索引为非常坏的元组列表,然后是第一次出现“坏”的索引:

import random

df = pd.DataFrame({
    'measure': [random.randint(0,10) for _ in range(0,20)],
})

df['status'] = df.apply(
    lambda x: 'good' if x['measure'] > 4 else 'very bad' if x['measure'] < 2  else 'bad',
    axis=1)
Run Code Online (Sandbox Code Playgroud)

这是数据框:

    measure    status
0         8      good
1         8      good
2         0  very bad
3         5      good
4         2       bad
5         3       bad
6         9      good
7         9      good
8        10      good
9         5      good
10        1  very bad
11        7      good
12        7      good
13        6      good
14        5      good
15       10      good
16        3       bad
17        0  very bad
18        3       bad
Run Code Online (Sandbox Code Playgroud)

我怎样才能得到这样组合的元组?

[(2,4), (10,16), (17,18)]

ank*_*_91 7

IIUC,你可以试试:

# filters only rows with bad and very bad
m = df[df['status'].isin(['bad','very bad'])] 

# check id current row is very bad and next row is bad
c = m['status'].eq('very bad') & m['status'].shift(-1).eq('bad')

# if true return next row as true too and get only index values
idx = m[c|c.shift()].index

# convert every 2 items into a tuple
res = [*zip(idx[::2],idx[1::2])]

Run Code Online (Sandbox Code Playgroud)
[(2, 4), (10, 16), (17, 18)]
Run Code Online (Sandbox Code Playgroud)

  • @r.ook 我不这么认为朋友。我已经看到你的回答,我可以保证你的智力:-) bdw 如果你需要更多解释,请告诉我。 (2认同)