Pra*_*tha 1 sql postgresql postgresql-12
我有 3 个复杂的表。对于这个问题,我就简化一下用法。我需要排名、计数(重复)和唯一记录(结果)。它适用于单个表,但是,当WITH包含并INNER JOIN给出另一个表时,我不再获得任何记录。
CREATE TABLE public.emails (
id bigint NOT NULL PRIMARY KEY GENERATED BY DEFAULT AS IDENTITY
(MAXVALUE 9223372036854775807),
sender jsonb NOT NULL
);
CREATE TABLE public.contacts (
id bigint NOT NULL PRIMARY KEY GENERATED BY DEFAULT AS IDENTITY
(MAXVALUE 9223372036854775807),
email text NOT NULL,
full_name text NOT NULL
);
-- sample data
insert into emails (sender) VALUES ('{"email": "dennis1@example.com", "name": "dennis1"}');
insert into emails (sender) VALUES ('{"email": "dennis1@example.com", "name": "dennis1"}');
insert into contacts (email, full_name) VALUES ('dennis1@example.com', 'dennis1');
insert into contacts (email, full_name) VALUES ('dennis1@example.com', 'dennis1');
insert into contacts (email, full_name) VALUES ('dennis5@example.com', 'dennis5');
insert into contacts (email, full_name) VALUES ('john@example.com', 'john');
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email name rk count
dennis1@example.com dennis1 1 4
dennis5@example.com dennis5 1 1
john@example.com john 1 1
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但是,我有两个问题:
INNER JOIN结果为零ORDER BY "count"不起作用。正如您所看到的,表格是不同的。一张表有jsonb列,另一张表存储为text. 因此,我分别提取每个SELECT查询中的内容然后进行比较。
所以我需要的是,获取所有电子邮件和姓名,使它们唯一,计算它们是否重复并排名。我不需要重复的条目,但将它们合并到count.
我怎么解决这个问题?
请参阅此处的演示:https://dbfiddle.uk/?rdbms =postgres_12&fiddle=b79700f74bbf14e190d5f5bf7fcd0670
在分组和应用窗口函数之前提取 json 并合并两个数据集。
WITH united as (
SELECT email, full_name FROM contacts
UNION ALL
SELECT sender->>'email', sender->>'name' FROM emails
)
SELECT
email
, full_name
, count(*) count, row_number() over (partition by email) rk
FROM united
GROUP BY 1, 2;
email | full_name | count | rk
---------------------+-----------+-------+----
dennis1@example.com | dennis1 | 4 | 1
dennis5@example.com | dennis5 | 1 | 1
john@example.com | john | 1 | 1
(3 rows)
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