正则表达式反编译器

jm6*_*666 4 regex perl

我找到了这个正则表达式,想要了解它.是否有任何正则表达式反编译器将以下正则表达式转换为单词?这真的很复杂.

$text =~ /(((\w)\W*(?{$^R.(0+( q{a}lt$3))})) {8}(?{print +pack"B8" ,$^Rand ""})) +/x;
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ken*_*ytm 17

使用YAPE::Regex::Explain(不确定它是否好,但它是搜索的第一个结果):

use YAPE::Regex::Explain;
my $REx = qr/(((\w)\W*(?{$^R.(0+( q{a}lt$3))})) {8}(?{print +pack"B8" ,$^Rand ""})) +/x;
my $exp = YAPE::Regex::Explain->new($REx)->explain;
print $exp;
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我的解释如下:

  (                        group and capture to \1 (1 or more times
                           (matching the most amount possible)):
----------------------------------------------------------------------
    (                        group and capture to \2 (8 times):
----------------------------------------------------------------------
      (                        group and capture to \3:
----------------------------------------------------------------------
        \w                       word characters (a-z, A-Z, 0-9, _)
----------------------------------------------------------------------
      )                        end of \3
----------------------------------------------------------------------
      \W*                      non-word characters (all but a-z, A-Z,
                               0-9, _) (0 or more times (matching the
                               most amount possible))
----------------------------------------------------------------------
      (?{$^R.(0+(              run this block of Perl code
      q{a}lt$3))})
----------------------------------------------------------------------
    ){8}                     end of \2 (NOTE: because you are using a
                             quantifier on this capture, only the
                             LAST repetition of the captured pattern
                             will be stored in \2)
----------------------------------------------------------------------
    (?{print +pack"B8"       run this block of Perl code
    ,$^Rand ""})
----------------------------------------------------------------------
  )+                       end of \1 (NOTE: because you are using a
                           quantifier on this capture, only the LAST
                           repetition of the captured pattern will be
                           stored in \1)

有2个Perl代码块,必须单独分析.

在第一个块中:

$^R . (0 + (q{a} lt $3))
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这里$^R "评估最后一次成功的(?{ code })正则表达式断言的结果",(0 + (q{a} lt $3))如果第三次捕获是在[b-z],表达式给出1 ,否则为0.

在第二块:

print +pack "B8", $^R and ""
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它将以前的评估结果解释为(big-endian)二进制字符串,获取数字,将其转换为相应的字符,最后将其打印出来.


正则表达式一起找到每8个字母数字字符,然后将它们[b-z]视为二进制数字1,否则为0.然后将这8个二进制数字解释为字符代码,并打印出该字符.

例如,匹配字符串时将打印字母"H"= 0b01001000

$test = 'OvERfLOW';
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