从Spring MVC控制器中的Security Context获取UserDetails对象

dan*_*nik 65 java spring spring-mvc spring-security

我正在使用Spring Security 3和Spring MVC 3.05.

我想打印当前登录用户的用户名,如何在Controller中获取UserDetails?

@RequestMapping(value="/index.html", method=RequestMethod.GET)
    public ModelAndView indexView(){
         UserDetails user = ?
                mv.addObject("username", user.getUsername());
        ModelAndView mv = new ModelAndView("index");
        return mv;
    }   
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sou*_*ica 114

如果您已经确定用户已登录(在您的示例中,如果/index.html受到保护):

UserDetails userDetails =
 (UserDetails)SecurityContextHolder.getContext().getAuthentication().getPrincipal();
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要首先检查用户是否已登录,请检查当前Authentication是否为a AnonymousAuthenticationToken.

Authentication auth = SecurityContextHolder.getContext().getAuthentication();
if (!(auth instanceof AnonymousAuthenticationToken)) {
        // userDetails = auth.getPrincipal()
}
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  • 这给了我一个例外:`java.lang.ClassCastException:java.lang.String无法强制转换为org.springframework.security.core.userdetails.UserDetails` (12认同)

Far*_*arm 32

让Spring 3注射解决这个问题.

感谢tsunade21,最简单的方法是:

 @RequestMapping(method = RequestMethod.GET)   
 public ModelAndView anyMethodNameGoesHere(Principal principal) {
        final String loggedInUserName = principal.getName();

 }
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