PHP比较时间

Question

如何在PHP中比较时间？

我想这样说:

$ThatTime ="14:08:10";
$todaydate = date('Y-m-d');
$time_now=mktime(date('G'),date('i'),date('s'));
$NowisTime=date('G:i:s',$time_now);
if($NowisTime >= $ThatTime) {
    echo "ok";
}

上面的代码打印不正常.我期待它.

Answer 1

$ThatTime ="14:08:10";
if (time() >= strtotime($ThatTime)) {
  echo "ok";
}

使用DateTime(也考虑时区)的解决方案.

$dateTime = new DateTime($ThatTime);
if ($dateTime->diff(new DateTime)->format('%R') == '+') {
  echo "OK";
}

http://php.net/datetime.diff

Answer 2

要看到当前时间大于或等于14:08:10,请执行以下操作:

if (time() >= strtotime("14:08:10")) {
  echo "ok";
}

根据您的输入来源,请务必考虑时区.

请参阅PHP time() 和PHP strtotime()

Answer 3

比较时间的简单方法是:

$time = date('H:i:s',strtotime("11 PM"));
if($time < date('H:i:s')){
     // your code
}