Haskell 一直给我输入错误

Question

不知道我做错了什么

type Name = String
type Location = (Float,Float)
type RainfallFigures = [Int]
type Place = (Name,Location,RainfallFigures)

rtnClosestDryPlace :: (Location -> Int -> [Place] -> [(Name,Float)]) -> (Name,Float)
rtnClosestDryPlace p1 n ((a,p2,c):xs) = rtnLowestDistance (distanceList p1 (rtnFullDryPlaces ((a,p2,c):xs) n))

    Couldn't match expected type ‘(Name, Float)’
                      with actual type ‘Int
                    -> [(Name, Location, RainfallFigures)] -> (Name, Float)’
        • The equation(s) for ‘rtnClosestDryPlace’ have three arguments,
          but its type ‘(Location -> Int -> [Place] -> [(Name, Float)])
                        -> (Name, Float)’
          has only one
    rtnClosestDryPlace p1 n ((a,p2,c):xs) = rtnLowestDistance (distanceList p1 (rtnFullDryPlaces ((a,p2,c):xs) n))
       | ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^



    template.hs:90:73: error:
        • Couldn't match expected type ‘(Float, Float)’
                      with actual type ‘Location -> Int -> [Place] -> [(Name, Float)]’
        • Probable cause: ‘p1’ is applied to too few arguments
          In the first argument of ‘distanceList’, namely ‘p1’
          In the first argument of ‘rtnLowestDistance’, namely
            ‘(distanceList p1 (rtnFullDryPlaces ((a, p2, c) : xs) n))’
          In the expression:
            rtnLowestDistance
              (distanceList p1 (rtnFullDryPlaces ((a, p2, c) : xs) n))
       |
    90 | rtnClosestDryPlace p1 n ((a,p2,c):xs) = rtnLowestDistance (distanceList p1 (rtnFullDryPlaces ((a,p2,c):xs) n))
       |          ^^

Location, Int, [place] 都被发送到一个返回 [(Name, Float)] 的函数，该函数又被发送到一个返回 (Name,Float) 的函数我不知道为什么这个程序不能运行. 为什么不能匹配类型

编辑：重写函数后，我设法正确地写下来，没有匹配错误

Answer 1

你的类型不对：

rtnClosestDryPlace :: (Location -> Int -> [Place] -> [(Name,Float)]) -> (Name,Float)

意味着这rtnClosestDryPlace是一个函数，其输入参数具有类型

(Location -> Int -> [Place] -> [(Name,Float)]) 

并且其输出参数具有类型

(Name,Float)

因此，该类型承诺，给定 3 个参数的函数，下面的代码能够返回一对。那不是你想要的。

我猜你真的想要类似的东西

rtnClosestDryPlace :: Location -> Int -> [Place] -> [(Name,Float)]