我需要比较两个缓冲区块以获得相等性.我不需要有关两个缓冲区关系的信息,只要两个块相等或不相等.我的intel机器支持SSE4.2
天真的方法是:
const size_t CHUNK_SIZE = 16; //128bit for SSE2 integer registers
const int ARRAY_SIZE = 200000000;
char* array_1 = (char*)_aligned_malloc(ARRAY_SIZE, 16);
char* array_2 = (char*)_aligned_malloc(ARRAY_SIZE, 16);
for (size_t i = 0; i < ARRAY_SIZE; )
{
volatile bool result = memcmp(array_1+i, array_2+i, CHUNK_SIZE);
i += CHUNK_SIZE;
}
Run Code Online (Sandbox Code Playgroud)
与我第一次尝试使用SSE相比:
union U
{
__m128i m;
volatile int i[4];
} res;
for (size_t i = 0; i < ARRAY_SIZE; )
{
__m128i* pa1 = (__m128i*)(array_1+i);
__m128i* pa2 = (__m128i*)(array_2+i);
res.m = _mm_cmpeq_epi32(*pa1, *pa2);
volatile bool result = ( (res.i[0]==0) || (res.i[1]==0) || (res.i[2]==0) || (res.i[3]==0) );
i += CHUNK_SIZE;
}
Run Code Online (Sandbox Code Playgroud)
速度增益约为33%.我可以做得更好吗?
您确实不应该使用标量代码和联合来测试所有单独的向量元素 - 相反,请执行以下操作:
for (size_t i = 0; i < ARRAY_SIZE; i += CHUNK_SIZE)
{
const __m128i a1 = _mm_load_si128(array_1 + i);
const __m128i a2 = _mm_load_si128(array_2 + i);
const __m128i vcmp = _mm_cmpeq_epi32(a1, a2);
const int vmask = _mm_movemask_epi8(vcmp);
const bool result = (vmask == 0xffff);
// you probably want to break here if you get a mismatch ???
}
Run Code Online (Sandbox Code Playgroud)