如何打印 pandas.io.formats.style.Styler 对象

Leo*_*ckl 4 python dataframe pandas

我有以下代码生成一个 pandas.io.formats.style.Styler 对象:

import pandas as pd
import numpy as np

df = pd.DataFrame({'text': ['foo foo', 'bar bar'],
                 'number': [1, 2]})

df1 = df.style.set_table_styles([dict(selector='th', props=[('text-align', 'center')])])
df2 = df1.set_properties(**{'text-align': 'center'}).hide_index()
df2   # df2 is a pandas.io.formats.style.Styler object
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df2如果在上述脚本下运行更多代码,我该如何打印,例如:

import pandas as pd
import numpy as np

df = pd.DataFrame({'text': ['foo foo', 'bar bar'],
                 'number': [1, 2]})

df1 = df.style.set_table_styles([dict(selector='th', props=[('text-align', 'center')])])
df2 = df1.set_properties(**{'text-align': 'center'}).hide_index()
df2

np.round(0.536, 2)
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我尝试使用 print 语句,但它给了我如下输出:

import pandas as pd
import numpy as np

df = pd.DataFrame({'text': ['foo foo', 'bar bar'],
                 'number': [1, 2]})

df1 = df.style.set_table_styles([dict(selector='th', props=[('text-align', 'center')])])
df2 = df1.set_properties(**{'text-align': 'center'}).hide_index()
print(df2)

np.round(0.536, 2)
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<pandas.io.formats.style.Styler object at 0x000000000B4FAFC8>
0.54
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任何帮助将不胜感激。提前谢谢了。

Leo*_*ckl 7

我找到了答案:

import pandas as pd
from IPython.display import display
import numpy as np

df = pd.DataFrame({'text': ['foo foo', 'bar bar'],
                 'number': [1, 2]})

df1 = df.style.set_table_styles([dict(selector='th', props=[('text-align', 'center')])])
df2 = df1.set_properties(**{'text-align': 'center'}).hide_index()
display(df2)

np.round(0.536, 2)
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