Ano*_*oop 0 python django-rest-framework
我面临一个改变以下结构的问题.....
这是我得到的结构
{
"labels": [
"List A",
"List B",
"List C",
"List D"
],
"data": [
19,
25,
30,
32
],
"colors": [
"#e15759",
"#f28e2b",
"#76b7b2",
"#4e79a7"
],
}
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但是我想把下面的数据改成下面的方法
{
"category": "List D",
"value": 32,
"colors": "#e15759"
},
{
"category": "List C",
"value": 25
"colors": "#f28e2b"
},
{
"category": "List B",
"value": 30,
"colors": "#76b7b2"
},
{
"category": "List A",
"value": 19,
"colors" : "#4e79a7"
}
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这是我的代码
class AbcListAPI(APIView):
def get(self, request, format=None):
a = data_fuction()
return Response(a)
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在这段代码中,我从在我的代码的另一部分使用的函数 data_fuction 得到这个响应......所以我无法从那里编辑该响应......但在这个函数中我需要格式化这个代码....
您需要将一种结构转换为另一种结构的功能
data = {
"labels": [
"List A",
"List B",
"List C",
"List D"
],
"data": [
19,
25,
30,
32
],
"colors": [
"#e15759",
"#f28e2b",
"#76b7b2",
"#4e79a7"
],
}
def convert_data(data):
result = []
for l, d, c in zip(data['labels'], data['data'], data['colors']):
result.append({
'category': l,
'value': d,
'colors': c,
})
return result
print(convert_data(data))
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