固定它.
$data = base64_decode(str_replace(' ', '+', $_GET['data']));
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无论出于何种原因,Php正在将GET变量中的+转换为空格
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我试图解密在C#.NET中解密的字符串.
代码的结果各不相同,有几次最后的字符串解密了一些部分,其余部分是随机字符.
大多数时候"解密"字符串只是所有随机字符,我也尝试了一些Php函数来删除PKCS7填充,但没有一个修复了这个问题.
我在网站上看了几个类似的问题,但没有一个是有帮助的.
C#
// called as Response.Redirect(url + encryptParams(param));
private string encryptData(string data)
{
Rijndael aes = Rijndael.Create();
aes.KeySize = 256;
aes.BlockSize = 256;
aes.Mode = CipherMode.CBC;
aes.Padding = PaddingMode.PKCS7;
aes.Key = Convert.FromBase64String("b0dJN2c6cklVUX1qUGlFfGMweXRKbH5fSEMuXjAgfQo=");
ICryptoTransform crypto = aes.CreateEncryptor(aes.Key, aes.IV);
byte[] txt = ASCIIEncoding.UTF8.GetBytes(data);
byte[] cipherText = crypto.TransformFinalBlock(txt, 0, txt.Length);
return "&data=" + Convert.ToBase64String(cipherText) + "&iv=" + Convert.ToBase64String(aes.IV);
}
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PHP的:
$data = base64_decode($_GET['data']);
$iv = base64_decode($_GET['iv']);
echo "<br /><b>IV</b>: " . $_GET['iv'] .
"<br /><b>Encrypted String</b>: <br /><textarea>".$_GET['data']."</textarea>" .
"<br /><b>key size:</b> " . mcrypt_get_key_size ( MCRYPT_RIJNDAEL_256, MCRYPT_MODE_CBC) .
"<br /><b>block size:</b> " . mcrypt_get_block_size ( MCRYPT_RIJNDAEL_256, MCRYPT_MODE_CBC) .
"<br /><b>cipher:</b> " . mcrypt_get_cipher_name ( MCRYPT_RIJNDAEL_256 ) .
"<br /><b>iv size:</b> " . mcrypt_get_iv_size ( MCRYPT_RIJNDAEL_256, MCRYPT_MODE_CBC) . "<br />";
echo "Result: " .
mcrypt_decrypt
(
MCRYPT_RIJNDAEL_256,
base64_decode("b0dJN2c6cklVUX1qUGlFfGMweXRKbH5fSEMuXjAgfQo="),
$data,
MCRYPT_MODE_CBC,
$iv
);
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Php输出:
IV: WzsMlG39tfCGuX2EQM3vq8CoqGA xC0nW jICls8Cno =
key:b0dJN2c6cklVUX1qUGlFfGMweXRKbH5fSEMuXjAgfQo =
加密字符串: oLxa21fxfQGg0EJ5rwMjEzMblvcaTq0AInDAsD88wAkNeLqOdon0ukLjz49Hpp36KPTKcTGkj1f7EPYPAAbuADnr3Ff0zpptZkx2d22VRbHrMgj QLF9vDxQRT3er3UAXsAfKKTyW8qeSIgrzACFLX3yoro/bzWic rt7ED7y0jZ7a1Hci3GMz/4KhwaftarbV QQWStJlSOqdxAdmtRRe84Vi3085S6um51bNrh5QzGRH PcpucfqaTb3junfO9g67j2JUQaM/Tj1EGnv6oX3wATR/LuWyhnhrCH86u10I =
密钥大小: 32
块大小: 32
密码: Rijndael-256
iv大小: 32
结果:
/ci ^/c g s c (
原始字符串(JSON): {"user":"jsmith","firstName":"John","lastName":"Smith","phone":"12223334444.5555","email":"john.smith@domain. com","地址":"123 Some Street","address2":"apt 456","city":"Some City","state":"LA","zip":"55555"}
使用以下代码修复它。
$data = base64_decode(str_replace(' ', '+', $_GET['data']));
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无论出于何种原因,PHP 将 GET 变量中的 + 转换为空格。