我想使用xpath表达式来获取属性的值.
我期望以下工作
from lxml import etree
for customer in etree.parse('file.xml').getroot().findall('BOB'):
print customer.find('./@NAME')
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但这会给出一个错误:
Traceback (most recent call last):
File "bob.py", line 22, in <module>
print customer.find('./@ID')
File "lxml.etree.pyx", line 1409, in lxml.etree._Element.find (src/lxml/lxml.etree.c:39972)
File "/usr/local/lib/python2.7/dist-packages/lxml/_elementpath.py", line 272, in find
it = iterfind(elem, path, namespaces)
File "/usr/local/lib/python2.7/dist-packages/lxml/_elementpath.py", line 262, in iterfind
selector = _build_path_iterator(path, namespaces)
File "/usr/local/lib/python2.7/dist-packages/lxml/_elementpath.py", line 246, in _build_path_iterator
selector.append(ops[token[0]](_next, token))
KeyError: '@'
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我错在期待这个工作吗?
unu*_*tbu 56
find并且findall 只实现 XPath 的子集.它们的存在旨在提供与其他ElementTree实现(如ElementTree和cElementTree)的兼容性.
xpath相反,该方法提供对XPath 1.0的完全访问权限:
print customer.xpath('./@NAME')[0]
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但是,您可以改为使用get:
print customer.get('NAME')
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或者attrib:
print customer.attrib['NAME']
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