删除重复后的行

ANi*_*sus 5 sql sql-server sql-server-2005 gaps-and-islands sql-delete

我有一个用户登录和注销邮票列表.遗憾的是,LOGIN条目可能并不总是后跟LOGOUT条目.
我希望在[event_date]命令时删除与前一行具有相同[event][user_id]的任何行. 有关如何执行此操作的建议吗?

示例表

CREATE TABLE #LOG (
    [id] int IDENTITY(1,1),
    [user_id] int,
    [event] varchar(50),
    [event_date] datetime
);
INSERT INTO #LOG ([user_id], [event], [event_date])
SELECT 1,'LOGIN',{ts '2010-12-15 15:31:59'}
UNION ALL SELECT 1,'LOGOUT',{ts '2010-12-15 15:32:55'}
UNION ALL SELECT 1,'LOGIN',{ts '2010-12-15 15:38:04'}
UNION ALL SELECT 1,'LOGOUT',{ts '2010-12-15 15:38:17'}
UNION ALL SELECT 1,'LOGOUT',{ts '2010-12-15 15:38:45'} -- Delete
UNION ALL SELECT 2,'LOGIN',{ts '2010-12-15 16:59:39'}
UNION ALL SELECT 2,'LOGOUT',{ts '2010-12-15 17:00:08'}
UNION ALL SELECT 2,'LOGOUT',{ts '2010-12-15 17:00:39'} -- Delete
UNION ALL SELECT 2,'LOGOUT',{ts '2010-12-15 17:01:16'} -- Delete
UNION ALL SELECT 2,'LOGIN',{ts '2010-12-15 17:01:38'}
UNION ALL SELECT 2,'LOGIN',{ts '2010-12-15 17:02:26'} -- Delete
UNION ALL SELECT 2,'LOGOUT',{ts '2010-12-15 17:02:39'}
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Mar*_*ith 3

;WITH T1 AS
(
SELECT * , 
        ROW_NUMBER() OVER (ORDER BY event_date)-
        ROW_NUMBER() OVER (PARTITION BY [user_id], [event] 
                               ORDER BY event_date) AS Grp
FROM #LOG
),T2 AS
(
SELECT 
   ROW_NUMBER() OVER (PARTITION BY [user_id], [event], Grp 
                          ORDER BY event_date) RN
FROM T1
)
DELETE FROM T2 
WHERE RN > 1
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