将秒值转换为小时分钟秒？

Question

我一直在尝试将秒值(在BigDecimal变量中)转换为editText中的字符串,如"1小时22分33秒"或类似的东西.

我试过这个:

String sequenceCaptureTime = "";
BigDecimal roundThreeCalc = new BigDecimal("0");
BigDecimal hours = new BigDecimal("0");
BigDecimal myremainder = new BigDecimal("0");
BigDecimal minutes = new BigDecimal("0");
BigDecimal seconds = new BigDecimal("0");
BigDecimal var3600 = new BigDecimal("3600");
BigDecimal var60 = new BigDecimal("60");

(我有一个roundThreeCalc,这是秒的值,所以我尝试在这里转换它.)

hours = (roundThreeCalc.divide(var3600));
myremainder = (roundThreeCalc.remainder(var3600));
minutes = (myremainder.divide(var60));
seconds = (myremainder.remainder(var60));
sequenceCaptureTime =  hours.toString() + minutes.toString() + seconds.toString();

然后我将editText设置为sequnceCaptureTime String.但那没用.它每次强制关闭应用程序.我完全超出了我的深度,非常感谢任何帮助.快乐的编码!

Answer 1

是否有必要使用BigDecimal？如果你没有,我会使用int或long for seconds,它会简化一些事情:

hours = totalSecs / 3600;
minutes = (totalSecs % 3600) / 60;
seconds = totalSecs % 60;

timeString = String.format("%02d:%02d:%02d", hours, minutes, seconds);

您可能想要填充每个以确保它们是字符串中的两位数值(或其他).

Answer 2

DateUtils.formatElapsedTime(long),以" MM:SS"或" H:MM:SS" 形式格式化已用时间.它返回您要查找的String.你可以在这里找到文档

Answer 3

你应该有更多的运气

hours = roundThreeCalc.divide(var3600, BigDecimal.ROUND_FLOOR);
myremainder = roundThreeCalc.remainder(var3600);
minutes = myremainder.divide(var60, BigDecimal.ROUND_FLOOR);
seconds = myremainder.remainder(var60);

这将在每次除法后删除小数值.

编辑:如果这不起作用,试试这个.(我刚刚编写并测试过它)

public static int[] splitToComponentTimes(BigDecimal biggy)
{
    long longVal = biggy.longValue();
    int hours = (int) longVal / 3600;
    int remainder = (int) longVal - hours * 3600;
    int mins = remainder / 60;
    remainder = remainder - mins * 60;
    int secs = remainder;

    int[] ints = {hours , mins , secs};
    return ints;
}

Answer 4

这是工作代码:

private String getDurationString(int seconds) {

    int hours = seconds / 3600;
    int minutes = (seconds % 3600) / 60;
    seconds = seconds % 60;

    return twoDigitString(hours) + " : " + twoDigitString(minutes) + " : " + twoDigitString(seconds);
}

private String twoDigitString(int number) {

    if (number == 0) {
        return "00";
    }

    if (number / 10 == 0) {
        return "0" + number;
    }

    return String.valueOf(number);
}

Answer 5

Java 8中真正有用的东西

import java.time.LocalTime;

private String ConvertSecondToHHMMSSString(int nSecondTime) {
    return LocalTime.MIN.plusSeconds(nSecondTime).toString();
}

Answer 6

我更喜欢java内置的TimeUnit库

long seconds = TimeUnit.MINUTES.toSeconds(8);

Answer 7

private String ConvertSecondToHHMMString(int secondtTime)
{
  TimeZone tz = TimeZone.getTimeZone("UTC");
  SimpleDateFormat df = new SimpleDateFormat("HH:mm:ss");
  df.setTimeZone(tz);
  String time = df.format(new Date(secondtTime*1000L));

  return time;

}

Answer 8

如果你想要单位h，min并且sec在一段时间内你可以使用这个：

public static String convertSeconds(int seconds) {
    int h = seconds/ 3600;
    int m = (seconds % 3600) / 60;
    int s = seconds % 60;
    String sh = (h > 0 ? String.valueOf(h) + " " + "h" : "");
    String sm = (m < 10 && m > 0 && h > 0 ? "0" : "") + (m > 0 ? (h > 0 && s == 0 ? String.valueOf(m) : String.valueOf(m) + " " + "min") : "");
    String ss = (s == 0 && (h > 0 || m > 0) ? "" : (s < 10 && (h > 0 || m > 0) ? "0" : "") + String.valueOf(s) + " " + "sec");
    return sh + (h > 0 ? " " : "") + sm + (m > 0 ? " " : "") + ss;
}

int seconds = 3661;
String duration = convertSeconds(seconds);

这是很多条件运算符。该方法将返回这些字符串：

0    -> 0 sec
5    -> 5 sec
60   -> 1 min
65   -> 1 min 05 sec
3600 -> 1 h
3601 -> 1 h 01 sec
3660 -> 1 h 01
3661 -> 1 h 01 min 01 sec
108000 -> 30 h

Answer 9

这是我的简单解决方案:

String secToTime(int sec) {
    int seconds = sec % 60;
    int minutes = sec / 60;
    if (minutes >= 60) {
        int hours = minutes / 60;
        minutes %= 60;
        if( hours >= 24) {
            int days = hours / 24;
            return String.format("%d days %02d:%02d:%02d", days,hours%24, minutes, seconds);
        }
        return String.format("%02d:%02d:%02d", hours, minutes, seconds);
    }
    return String.format("00:%02d:%02d", minutes, seconds);
}

Test Results:

Result: 00:00:36 - 36
Result: 01:00:07 - 3607
Result: 6313 days 12:39:05 - 545488745

Answer 10

因此，我喜欢保持简单：

    int tot_seconds = 5000;
    int hours = tot_seconds / 3600;
    int minutes = (tot_seconds % 3600) / 60;
    int seconds = tot_seconds % 60;

    String timeString = String.format("%02d Hour %02d Minutes %02d Seconds ", hours, minutes, seconds);

    System.out.println(timeString);

结果将是：01小时23分钟20秒

Answer 11

java.time 的持续时间

    BigDecimal secondsValue = BigDecimal.valueOf(4953);
    if (secondsValue.compareTo(BigDecimal.valueOf(Long.MAX_VALUE)) > 0) {
        System.out.println("Seconds value " + secondsValue + " is out of range");
    } else {
        Duration dur = Duration.ofSeconds(secondsValue.longValueExact());
        long hours = dur.toHours();
        int minutes = dur.toMinutesPart();
        int seconds = dur.toSecondsPart();

        System.out.format("%d hours %d minutes %d seconds%n", hours, minutes, seconds);
    }

该片段的输出是：

1小时22分33秒

如果此代码中存在非零的秒分数，则BigDecimal该代码将无法正常工作，但您可以对其进行修改。该代码适用于 Java 9 及更高版本。在 Java 8 中，从小时、分钟和秒的转换Duration有点冗长，请参阅底部的链接了解具体方法。我让您选择单词的正确单数或复数形式（hour或hours等）。

链接

• Oracle 教程：日期时间解释如何使用 java.time。
• lauhub 的回答显示了 Java 8 中从 a 到天、小时、分钟和秒的转换Duration。

Answer 12

这段代码工作正常：

txtTimer.setText(String.format("%02d:%02d:%02d",(SecondsCounter/3600), ((SecondsCounter % 3600)/60), (SecondsCounter % 60)));