我有一张结构如下的地图:
"Alex": [Work(workPlace="workPlace", years=1),
Work(workPlace="workPlace", years=4),
Work(workPlace="workPlace", years=5),
Work(workPlace="workPlace", years=1)],
"John": [Work(workPlace="workPlace", years=2),
Work(workPlace="workPlace", years=2),
Work(workPlace="workPlace", years=1),
Work(workPlace="workPlace", years=6)]
Run Code Online (Sandbox Code Playgroud)
求和这些值的最佳方法是什么?
例如,我如何总结亚历克斯和约翰的所有这些年?
zsm*_*b13 10
我认为您主要是在寻找该mapValues
函数,该函数允许您转换地图的值,同时保留其键。你可以这样使用它:
val people: Map<String, List<Work>> = ...
val peopleToSumOfYears: Map<String, Int> =
people.mapValues { (name, works) -> works.sumOf { it.years } }
Run Code Online (Sandbox Code Playgroud)
归档时间: |
|
查看次数: |
6422 次 |
最近记录: |