使用 MapStruct 将抽象类映射到 DTO

Question

我发现了很多与此相关的主题，但在我看来，所有解决方案都走向了错误的方向。

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那么...在这种情况下我该如何使用 MapStruct 映射？

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抽象类人：

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public abstract class Person implements Serializable{\n\n     private String name;\n     private String somethingToIgnore\n\n     //Getter and Setter\n\n}\n

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普通的映射器不能\xc2\xb4工作：

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@Mapper(componentModel = 'cdi')\npublic interface PersonMapper{\n\n    @Mapping(target = 'somethingToIgnore', ignore = 'true')\n    Person toPerson(PersonDTO source);\n\n    @InheritInverseConfiguration\n    PersonDTO toPersonDtO(Person source);\n\n}\n

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我不允许映射抽象类。我应该使用工厂方法。我尝试过，但我根本不知道这个工厂方法应该是什么样子......

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我的尝试：

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@Mapper\npublic interface PersonMapper {\n\n    PersonMapper INSTANCE = Mappers.getMapper( PersonMapper.class );\n\n    Person toPerson(PersonDTO source);\n\n    PersonDTO toPersonDtO(Person source);\n}\n\n

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@Mapper\npublic abstract class PersonMapper {\n\n    public static final PersonMapper INSTANCE = Mappers.getMapper( PersonMapper.class );\n\n    Person toPerson(PersonDTO source);\n\n    PersonDTO toPersonDtO(Person source);\n}\n\n

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我错过了什么并且做错了什么？\n提前致谢。

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Answer 1

MapStruct doesn't know how to map to abstract class, because it cannot instantiate it. I expect that you have some implementation of Person. You need to provide method which will create object of a Person like this:

@Mapper
public interface PersonMapper {

    Person toPerson(PersonDTO source);

    PersonDTO toPersonDtO(Person source);

    default Person createPerson() {
        return new PersonImpl();
    }
}

This way MapStruct will use this method to create Person instance and than map the properties like usual. You can find more about object factories in the documentation.