Spring 文档 - Open API 3 - 如何为正文设置默认值?

PAA*_*PAA 4 spring springdoc springdoc-openui

我使用Spring Boot + Spring Data Mongo + Spring REST + Spring HATEOAS来实现 REST 端点。

由于我们传递了超过 5 个查询参数(组织的专有设置,应该不传递),所以我想创建一个 EmployeeDto 类并在 Controller 处传递该类

@GetMapping(value = "/employees", produces = {MediaType.APPLICATION_JSON })
public ResponseEntity<PagedModel<EmployeeModel>> findEmployees(
        EmployeeDto dto,
        @Parameter(hidden=true) String sort,
        @Parameter(hidden=true) String order,
        @Parameter(hidden=true) Pageable pageRequest) {

    // Add needed logic 
    ......
    ......
    ......
    PagedModel<EmployeeModel> model = employeePagedAssembler.toModel(response, employeeAssembler);

    return new ResponseEntity<>(model, HttpStatus.OK);
}
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Swagger UI 显示如下 -

{
  "firstName": "string",
  "lastName": "string",
  "age": 0,
  "languageCd": "string",
  "isActive": "string",
  "email": "string",
  "regionCd": "string"
}
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卷曲命令:

curl -X GET " http://localhost:8080/employee-data/employees/geographies?firstName=string&lastName=string&age=0&languageCd=string&isActive=string&email=string®ionCd=string&page=0&size=25&sort=firstName&order=ASC " -H " 接受:应用程序/json”

EmployeeDto.java

@AllArgsConstructor
@NoArgsConstructor
@Data
@Builder
@Schema
public class EmployeeDto {
    @Schema(description = AppConstants.FIRSTNAME, defaultValue="")
    private String firstName; 

    @Schema(description = AppConstants.LASTNAME, defaultValue="")
    private String lastName; 

    @Schema(description = AppConstants.AGE, defaultValue="")
    private Integer age; 

    @Schema(description = AppConstants.LANG_CD_DESC, defaultValue="0")
    private String languageCd;

    @Schema(description = AppConstants.ISACTIVE, defaultValue="")
    private String isActive; 

    @Schema(description = AppConstants.EMAIL, defaultValue="")
    private String email; 

    @Schema(description = AppConstants.REGION_CD_DESC, defaultValue="")
    private String regionCd;
}
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我在寻找 -

1)如何为每个字段设置默认值而不是默认的“字符串”?

2)如何简单地允许在OAS3 UI中查看实际查询参数?货币,它看起来像身体。

PAA*_*PAA 5

我能够自己解决这个问题。example - Provides an example of the schema. When associated with a specific media type, the example string shall be parsed by the consumer to be treated as an object or an array.

代码 -

@AllArgsConstructor
@NoArgsConstructor
@Data
@Builder
@Schema
public class EmployeeDto {
    @Schema(description = AppConstants.FIRSTNAME, type = "string", example = " ")
    private String firstName; 

    @Schema(description = AppConstants.LASTNAME, type = "string", example = " ")
    private String lastName; 

    @Schema(description = AppConstants.AGE, type = "string", example = "null")
    private Integer age; 

    @Schema(description = AppConstants.LANG_CD_DESC, type = "string", example = " ")
    private String languageCd;

    @Schema(description = AppConstants.ISACTIVE, type = "string", example = " ")
    private String isActive; 

    @Schema(description = AppConstants.EMAIL, type = "string", example = " ")
    private String email; 

    @Schema(description = AppConstants.REGION_CD_DESC, type = "string", example = " ")
    private String regionCd;
}
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并在控制器中只需添加以下方法,如果"null"发送了值,该方法将重置,如果是,则将其重置为,对于to""也是如此。Integernull

public static Object getDefaulter(Object obj) {
    Arrays.stream(obj.getClass().getDeclaredFields()).map(f -> {
        f.setAccessible(true);
        try {
            // set null values only if found String value as "null"
            if (Objects.equals(f.get(obj), "null")) {
                f.set(obj, "");
            }else if(Objects.equals(f.get(obj), 0)) {
                f.set(obj, null);
            }
        } catch (IllegalArgumentException | IllegalAccessException e) {
            //
        }
        return f;
    }).collect(Collectors.toList());
    return obj;
}
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