猜数字 - 读错时无限循环

Question

所以我猜这个用C++编写的数字游戏看起来像这样:

#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;

int main()
{
    srand(time(0));
    int secretNumber = rand() % 100 + 1; //Generate "Random number"
    int nbrOfGuesses = 0;
    int userInput;

    cout<<"\t************************************"<<endl;
    cout<<"\t*                                  *"<<endl;
    cout<<"\t*          Guess the number!       *"<<endl;
    cout<<"\t*                                  *"<<endl;
    cout<<"\t************************************"<<endl;
    cout<<endl;
    cout << "Try to find the secret int number: " << endl;

    //While input is good
    while(cin.good())
    {
        //Do this
        do {
            cin>>userInput;
            nbrOfGuesses++;

            if (userInput>secretNumber)
                cout << "Smaller!\n";

            else if(userInput<secretNumber)
                cout << "Bigger!\n"; // <-- Infinite loop here when you enter something other than an integer

            else //Also using this as a backup of (cin.good())
                cout << "Something went wrong with the read";
                break;

        } while(userInput!=secretNumber);
                cout << "\nCongratulations! You got it in " << nbrOfGuesses << " guesses\n";
    }

    system("pause");
    return 0;
}

*对不起,如果代码是非常优雅的

正如你所看到的,代码工作得很好,直到你输入一个随机的字符,如'&'或'j'或其他任何不是整数的...然后它循环在cout <<"Bigger!";

所以我的问题是:是什么导致了这个？

Answer 1

查看这篇文章,它是关于同样的问题.总结一下:

cin>>userInput;
if (cin.fail()) {
  cout<<"Invalid Entry, please try again."<<endl;
  cin.clear();
  cin.ignore(numeric_limits<streamsize>::max(), '\n');
}

感谢ildjarn指出丢失的忽略声明,我错过了那部分,即使它在我链接的帖子中明确提到!!