Axios - 获取带有参数的 url，而不实际发出请求

Question

我的 React 项目中有一些代码，如下所示：

        const url = '/create-label-shipments.json';
        const filters = Object.assign({}, this.state.filters);
        filters.page = this.state.page;
        const response = await axios.get(url, {params: filters});

现在我知道 axios 接受该params对象并使用查询参数创建一个新的 url，例如'/create-label-shipments.json?page=1&date=2020-03-20&etc...'

我希望我能做的是在代码的不同部分调用一些 axios 函数，其功能与上面完全相同，但它不是发出请求并给我响应，而是只给我 URL。

        const url = '/create-label-shipments.csv';
        const filters = Object.assign({}, this.state.filters);
        const url = await axios.getUrl(url, {params: filters});
        // at this point, no request was made, and url === '/create-label-shipments.csv?page=1&date=2020-03-20&etc...'

Answer 1

也许您正在寻找axios#getUri()，您可以通过将params属性和url属性添加到传递给方法的配置对象来使用它：

const params = {
  page: 1,
  date: '2020-03-20'
}

const url = '/create-label-shipments.csv';
const res = axios.getUri({url, params});

console.log(res);

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