Kle*_*ios 6 ansible ansible-vault
我正在使用 ansible 2.7.16。
\n\nansible 文档说:
\n\nSingle Encrypted Variable\n\nAs of version 2.3, Ansible can now use a vaulted variable that lives in an otherwise \xe2\x80\x98clear text\xe2\x80\x99 YAML file:\n\nnotsecret: myvalue\nmysecret: !vault |\n $ANSIBLE_VAULT;1.1;AES256\n 66386439653236336462626566653063336164663966303231363934653561363964363833313662\n 6431626536303530376336343832656537303632313433360a626438346336353331386135323734\n 62656361653630373231613662633962316233633936396165386439616533353965373339616234\n 3430613539666330390a313736323265656432366236633330313963326365653937323833366536\n 34623731376664623134383463316265643436343438623266623965636363326136\nother_plain_text: othervalue\nRun Code Online (Sandbox Code Playgroud)\n\n我有以下 .yml 文件:
\n\nuser: dbuser\npass: !vault |\n $ANSIBLE_VAULT;1.1;AES256\n 33633131346338633461336438656463643539396535656432306564636466353338373135346166\n 3838313236383739616239333265323131376231656633350a613333613239646263393330353930\n 31303935646330643831396130343031613063393839353433646338343034386432656435623934\n 6537356530643136310a373835323666393337346562613831613962323261346232323331343631\n 3838\nRun Code Online (Sandbox Code Playgroud)\n\n我想获得解密的文件,然后我尝试了以下命令:
\n\nansible-playbook --vault-password-file pass.txt config.yml
但我收到以下错误:
\n\n [WARNING]: Unable to parse /etc/ansible/hosts as an inventory source\n\n [WARNING]: No inventory was parsed, only implicit localhost is available\n\n [WARNING]: provided hosts list is empty, only localhost is available. Note that the implicit localhost does not match 'all'\n\nERROR! playbooks must be a list of plays\n\nThe error appears to have been in '/tmp/config.yml': line 1, column 1, but may\nbe elsewhere in the file depending on the exact syntax problem.\n\nThe offending line appears to be:\n\n\nuser: dbuser\n^ here\nRun Code Online (Sandbox Code Playgroud)\n\n如何获取变量已解密的 .yml 文件?
\n问:“如何解密 .yml 文件?”
答:只需像使用任何其他带有变量的文件一样使用该文件即可。例如
shell> ansible-vault encrypt_string 'password' --name 'pass'
pass: !vault |
$ANSIBLE_VAULT;1.1;AES256
65303631663061316538623639316439366538386430656239383735353237343762346364653230
3163643637333966643762383733633465353065333564310a303762343732613363313864646661
66633539363865386362613362663238353664356439386431303065646530666562326662356439
3032313564373364360a623830613763616635383633363631356535316162393138373336386534
3835
Run Code Online (Sandbox Code Playgroud)
shell> cat conf1.yml
pass: !vault |
$ANSIBLE_VAULT;1.1;AES256
65303631663061316538623639316439366538386430656239383735353237343762346364653230
3163643637333966643762383733633465353065333564310a303762343732613363313864646661
66633539363865386362613362663238353664356439386431303065646530666562326662356439
3032313564373364360a623830613763616635383633363631356535316162393138373336386534
3835
Run Code Online (Sandbox Code Playgroud)
shell> cat playbook.yml
- hosts: localhost
tasks:
- include_vars: conf1.yml
- debug:
var: pass
Run Code Online (Sandbox Code Playgroud)
给出
shell> ansible-playbook playbook.yml
...
"pass": "password"
Run Code Online (Sandbox Code Playgroud)
答:可以选择以相同的方式编辑decrypt文件。例如encrypt
shell> cat conf.yml
user: dbuser
shell> ansible-vault encrypt conf.yml
Encryption successful
shell> cat conf.yml
$ANSIBLE_VAULT;1.1;AES256
63313762343630623364653737643462373034653762616333663330613039623534633030666135
6633343263666465356537316430623834386130626231310a376639356234336664386239336461
31313935613565656639653532613639396536326662346234373563663065643564373939316539
3430643635623339390a393139326337306363623565356439626430643161356266323832313461
3633
shell> ansible-vault decrypt conf.yml
Decryption successful
shell> cat conf.yml
user: dbuser
Run Code Online (Sandbox Code Playgroud)
shell> cat playbook.yml
- hosts: localhost
tasks:
- include_vars: conf.yml
- debug:
var: user
Run Code Online (Sandbox Code Playgroud)
给出
shell> ansible-playbook playbook.yml
...
"user": "dbuser"
Run Code Online (Sandbox Code Playgroud)
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