WPF:如何设置UserControl显示的对话框的所有者窗口？

Question

我有一个WPF应用程序有这三种类型的东西......

• WindowMain
• UserControlZack
• WindowModal

UserControlZack1位于我的WindowMain上......

<Window x:Class="WindowMain"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        xmlns:local="clr-namespace:ProjectName"
        ...
        Name="WindowMain">
    <Grid>
        ...
        <local:UserControlZack x:Name="UserControlZack1" ... />
        ...
    </Grid>
</Window>

UserControlZack1显示一个WindowModal dailog框...

Partial Public Class UserControlZack

   ...

    Private Sub SomeButton_Click(...)
        'instantiate the dialog box and open modally...
        Dim box As WindowModal = New WindowModal()
        box.Owner = ?????
        box.ShowDialog()
        'process data entered by user if dialog box is accepted...
        If (box.DialogResult.GetValueOrDefault = True) Then
            _SomeVar = box.SomeVar
            ...
        End If
    End Sub

End Class

如何将box.Owner设置为正确的Window,我正在运行的WindowMain实例？

我无法使用box.Owner = Me.Owner,因为"'所有者'不是'ProjectName.UserControlZack'的成员."

我不能使用box.Owner = Me.Parent,因为它返回一个Grid,而不是Window.

我无法使用box.Owner = WindowMain,因为"'WindowMain'是一种类型,不能用作表达式."

Answer 1

尝试使用

.Owner = Window.GetWindow(this)

Answer 2

要获得顶级窗口,您的控件就在,假设有一个:

(Window)PresentationSource.FromVisual(this).RootVisual

要获得主窗口:

Application.Current.MainWindow

Answer 3

MyWpfDialog dialog = new MyWpfDialog();

//remember, this is WinForms UserControl and its Handle property is
//actually IntPtr containing Win32 HWND.

new System.Windows.Interop.WindowInteropHelper(dialog).Owner = this.Handle;

dialog.ShowDialog();

Answer 4

更新以尝试和帮助Greg的评论.该命令适用于主窗口菜单,用户控件中的按钮和用户控件中的上下文菜单.

我会用命令来做.所以有一个类Commands.cs类似于:

public static class Commands
{
    public static RoutedUICommand TestShowDialogCommand = new RoutedUICommand("Test command", "TestShowDialog", typeof(Commands));
}

在主窗口中注册这些:(你不需要canshow它默认为true)

    public Window1()
    {
        InitializeComponent();

        CommandManager.RegisterClassCommandBinding(typeof(System.Windows.Controls.Control),
            new CommandBinding(Commands.TestShowDialogCommand, ShowDialogCommand, CanShowDialogCommand));
    }

    private void ShowDialogCommand(object sender, ExecutedRoutedEventArgs e)
    {
        var box = new Window();
        box.Owner = this;
        box.ShowDialog();

    }

    private void CanShowDialogCommand(object sender, CanExecuteRoutedEventArgs e)
    {
        e.CanExecute = true;
    }

这是我的主窗口的xaml:

<Window x:Class="WpfApplication1.Window1"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:WpfApplication1="clr-namespace:WpfApplication1"
Title="Window1" Height="300" Width="322">
<Grid>
    <StackPanel>
        <Menu>
            <MenuItem Header="Test">
                <MenuItem Header="ShowDialog" Command="{x:Static WpfApplication1:Commands.TestShowDialogCommand}"/>
            </MenuItem>
        </Menu>
        <WpfApplication1:BazUserControl />
    </StackPanel>
</Grid>
</Window>

这是我的用户控件的xaml(仅限默认代码)

<UserControl x:Class="WpfApplication1.BazUserControl"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:WpfApplication1="clr-namespace:WpfApplication1"
Height="300" Width="300">
<Grid>
    <StackPanel>
        <Button Command="{x:Static WpfApplication1:Commands.TestShowDialogCommand}" Content="ClickMe" ></Button>
        <TextBox>
            <TextBox.ContextMenu>
                <ContextMenu>
                    <MenuItem Header="ShowDialog" Command="{x:Static WpfApplication1:Commands.TestShowDialogCommand}" />
                </ContextMenu>
            </TextBox.ContextMenu>
        </TextBox>
    </StackPanel>
</Grid>
</UserControl>

您可以更进一步,并在控制器类中处理该命令,并使其更多一点MVC.

Answer 5

我通过 XAML 一路爬回让它工作......

box.Owner = DirectCast(DirectCast(DirectCast(Me.Parent, Grid).Parent, Grid).Parent, Window)

但这似乎很不优雅。有没有更好的办法？