Pod*_*ays 137 sql sql-server date sql-server-2008
我想要获得两天之间的总天数:
1/1/2011
3/1/2011
RETURN
62
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是否可以在SQL Server中执行?
Wil*_*l A 272
PRINT DATEDIFF(DAY, '1/1/2011', '3/1/2011')
会给你你想要的东西.
这给出了两个日期之间跨越午夜边界的次数.如果您在计数中包含两个日期,您可能决定需要添加一个 - 或者如果您不想包含任何一个日期,则减去一个日期.
Khe*_*pri 38
DECLARE @startdate datetime2 = '2007-05-05 12:10:09.3312722';
DECLARE @enddate datetime2 = '2009-05-04 12:10:09.3312722';
SELECT DATEDIFF(day, @startdate, @enddate);
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jam*_*ams 16
您可以尝试此MSDN链接
DATEDIFF ( datepart , startdate , enddate )
SELECT DATEDIFF(DAY, '1/1/2011', '3/1/2011')
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Mit*_*eat 16
见DateDiff:
DECLARE @startdate date = '2011/1/1'
DECLARE @enddate date = '2011/3/1'
SELECT DATEDIFF(day, @startdate, @enddate)
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SELECT DATEDIFF(day, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
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