God*_*a74 2 ruby ruby-on-rails
我在我的 Rails 应用程序中嵌套了资源,基本上是一个Projecthas Targets,我认为创建关系的最简单方法是在我的 routes.rb 中执行此操作:
resource :projects do
resource :targets
end
Run Code Online (Sandbox Code Playgroud)
我的模型也非常匹配:
- Project.rb
class Project < ApplicationRecord
has_many :targets
end
- Target.rb
class Target < ApplicationRecord
has_one :project
end
Run Code Online (Sandbox Code Playgroud)
跑步rake routes向我展示了我的期望:
project_targets GET /projects/:project_id/targets(.:format) targets#index
POST /projects/:project_id/targets(.:format) targets#create
new_project_target GET /projects/:project_id/targets/new(.:format) targets#new
edit_project_target GET /projects/:project_id/targets/:id/edit(.:format) targets#edit
project_target GET /projects/:project_id/targets/:id(.:format) targets#show
PATCH /projects/:project_id/targets/:id(.:format) targets#update
PUT /projects/:project_id/targets/:id(.:format) targets#update
DELETE /projects/:project_id/targets/:id(.:format) targets#destroy
projects GET /projects(.:format) projects#index
POST /projects(.:format) projects#create
new_project GET /projects/new(.:format) projects#new
edit_project GET /projects/:id/edit(.:format) projects#edit
project GET /projects/:id(.:format) projects#show
PATCH /projects/:id(.:format) projects#update
PUT /projects/:id(.:format) projects#update
DELETE /projects/:id(.:format) projects#destroy
Run Code Online (Sandbox Code Playgroud)
完成此操作后,我的创建/编辑表单不再适用于target,因此我不得不调整form_forfrom的第一行:
<%= form_for @target do |f| %>
to
<%= form_for @target, url: project_targets_path do |f| %>
Run Code Online (Sandbox Code Playgroud)
注意我必须明确声明网址
Target控制器中的 create 方法非常基本:
def create
@target = Target.create(target_params)
if @target.valid?
redirect_to project_target_path(id: @target.id)
else
flash[:errors] = @target.errors.full_messages
redirect_to new
end
end
Run Code Online (Sandbox Code Playgroud)
我尝试创建一个目标是成功的,但目标没有project_id分配给它,每个 db 架构:
create_table :targets do |t|
t.string :domain
t.boolean :investigated, default: false
t.boolean :research, default: false
t.integer :project_id
t.timestamps
end
Run Code Online (Sandbox Code Playgroud)
这就是我在日志中看到的内容,显然它project_id是作为 URL 的一部分传递的,但它没有与创建时的新目标相关联。
Started POST "/projects/1/targets" for ::1 at 2020-03-13 19:19:57 -0400
Processing by TargetsController#create as HTML
Parameters: {"authenticity_token"=>"jLzQmpsxMRW4z66WguFVwZcLnMxFJYIy86EDfru6fIhysWDU/fd6yq5HV2uv1Z3TICGQSAXZDll66DwizReWaQ==", "target"=>{"domain"=>"2-test.com"}, "commit"=>"Create", "project_id"=>"1"}
(0.1ms) begin transaction
? app/controllers/targets_controller.rb:11:in `create'
Target Create (0.8ms) INSERT INTO "targets" ("domain", "created_at", "updated_at") VALUES (?, ?, ?) [["domain", "2-test.com"], ["created_at", "2020-03-13 23:19:57.097233"], ["updated_at", "2020-03-13 23:19:57.097233"]]
? app/controllers/targets_controller.rb:11:in `create'
(1.1ms) commit transaction
? app/controllers/targets_controller.rb:11:in `create'
Run Code Online (Sandbox Code Playgroud)
我的设置不正确吗?我该如何解决这个问题,以便在创建新目标时project_id包括在内?如果可能的话,我想保留这个 RESTful 并且在 project_id 中不传递隐藏字段。
将表格设置为:
<%= form_for [@project, @target] do |f| %>
Run Code Online (Sandbox Code Playgroud)
虽然您可以显式传递一个 url:
<%= form_for @target, url: project_targets_path(@project) do |f| %>
Run Code Online (Sandbox Code Playgroud)
如果您以部分形式共享表单,这将破坏edit和update操作,/projects/:project_id/targets/:id因为更新时操作属性应指向。更喜欢约定而不是配置。
你的 create 方法在很多方面也被破坏了。
class TargetsController < ApplicationController
before_action :set_project
before_action :set_target, except: [:new, :index]
# POST /projects/1/targets
def create
# building the new record off the parent sets the project_id
@target = @project.targets.new(target_params)
if @target.save
redirect_to [@project, @target]
else
flash[:errors] = @target.errors.full_messages
# When a record is invalid always render - never redirect.
render :new
end
end
private
def set_project
@project = Project.find(params[:project_id])
end
# ...
end
Run Code Online (Sandbox Code Playgroud)
if @project.valid?只检查应用程序验证是否已通过 - 而不是记录是否实际保存到数据库中。检查@target.saveor的返回值@target.persisted?。
请注意,:project_id不应包含在您的参数白名单中,因为它通过 url 而不是通过批量分配。嵌套路由确实与强参数没有任何关系。
您还应该阅读浅层嵌套,因为您很可能不需要嵌套成员路由,并且它大大降低了复杂性。
| 归档时间: |
|
| 查看次数: |
196 次 |
| 最近记录: |