错误[E0308]：类型不匹配 - 预期为“&str”，但找到了结构“std::string::String”

Question

我正在制作井字游戏。代码不完整，但我被困在这里。我想打印array_display到控制台，但是当我分配字符串时，会弹出错误。

use std::io;

fn main() {
    let mut player1: String = String::new();
    let mut player2: String = String::new();
    let mut positions = ["1", "2", "3", "4", "5", "6", "7", "8", "9"];

    let mut lets_play = true;

    println!("Welcome to tic tac toe");
    println!("Player 1 please select what symbol you want to be : (x or o)");
    io::stdin().read_line(&mut player1);

    player1 = player1.to_lowercase();
    println!("{:?}", player1);

    if player1.trim() == "x" {
        player1 = String::from("x");
        player2 = String::from("o");
        println!("Player 1 is x");
    } else if player1.trim() == "o" {
        player1 = String::from("o");
        player2 = String::from("x");
        println!("Player 1 is o");
    } else {
        println!("Input is not valid");
        lets_play = false;
    }
    if lets_play {
        println!("Let's start the game :");

        print_board(&mut positions);
    } else {
        println!("Please reset the game");
    }
}

fn print_board(arr: &mut [&str]) {
    let mut counter = 0;
    let mut array_display = ["1", "2", "3"];
    let mut array_position = 0;
    let mut string_for_array = String::new();

    for i in 0..arr.len() {
        string_for_array.push_str(arr[i]);
        counter += 1;
        if counter == 3 {
            println!(
                "array_display[{}] value =  {}",
                array_position, string_for_array
            );
            array_display[array_position] = string_for_array.to_string();
            println!("String to push {:?}", string_for_array);
            string_for_array = String::from("");
            println!("Array position {}", array_position);
            array_position += 1;
            counter = 0;
        }
    }
}

错误：

use std::io;

fn main() {
    let mut player1: String = String::new();
    let mut player2: String = String::new();
    let mut positions = ["1", "2", "3", "4", "5", "6", "7", "8", "9"];

    let mut lets_play = true;

    println!("Welcome to tic tac toe");
    println!("Player 1 please select what symbol you want to be : (x or o)");
    io::stdin().read_line(&mut player1);

    player1 = player1.to_lowercase();
    println!("{:?}", player1);

    if player1.trim() == "x" {
        player1 = String::from("x");
        player2 = String::from("o");
        println!("Player 1 is x");
    } else if player1.trim() == "o" {
        player1 = String::from("o");
        player2 = String::from("x");
        println!("Player 1 is o");
    } else {
        println!("Input is not valid");
        lets_play = false;
    }
    if lets_play {
        println!("Let's start the game :");

        print_board(&mut positions);
    } else {
        println!("Please reset the game");
    }
}

fn print_board(arr: &mut [&str]) {
    let mut counter = 0;
    let mut array_display = ["1", "2", "3"];
    let mut array_position = 0;
    let mut string_for_array = String::new();

    for i in 0..arr.len() {
        string_for_array.push_str(arr[i]);
        counter += 1;
        if counter == 3 {
            println!(
                "array_display[{}] value =  {}",
                array_position, string_for_array
            );
            array_display[array_position] = string_for_array.to_string();
            println!("String to push {:?}", string_for_array);
            string_for_array = String::from("");
            println!("Array position {}", array_position);
            array_position += 1;
            counter = 0;
        }
    }
}

Answer 1

代码中的当前问题是string_for_array.to_string()创建一个新的String，但array_display数组包含&str引用。

编译器在这里给出的建议（替换为&string_for_array.to_string()）不起作用，因为 的结果.to_string()将在行尾被释放，并且您将拥有无效的&str引用。

所以，问题是：某个变量需要拥有该字符串。由于string_for_array后来修改了，所以不能使用。自然的选择是array_display（因为那是该字符串无论如何都会存在的地方）。因此，首先修改此数组以包含拥有的String而不是&str引用：

    let mut array_display = ["1".to_owned(), "2".to_owned(), "3".to_owned()];

然后其余的代码将编译。