python或pyqt - 检查鼠标按钮单击状态

mic*_*use 5 python mouse release pyqt click

我需要检查是否单击或释放了鼠标按钮.我正在使用pyqt - 以任何方式检查qt中的鼠标按钮释放状态或直接在python中?

我知道pygame模块,但不想安装它.

Kab*_*bie 7

检查你的文档 PyQt4/doc/html/qt.html#MouseButton-enum

Constant    Value
Qt.NoButton 0x00000000
Qt.LeftButton   0x00000001
Qt.RightButton  0x00000002
Qt.MidButton    0x00000004
Qt.MiddleButton MidButton
Qt.XButton1 0x00000008
Qt.XButton2 0x00000010
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一个简单的例子:

>>> from PyQt4 import QtCore, QtGui
>>> app=QtGui.QApplication([])
>>> mouse_state=app.mouseButtons()
>>> mouse_state==QtCore.Qt.NoButton
True
>>> int(mouse_state)
0
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