iOS 13 > 当应用程序被杀死且不在后台时，通用应用程序链接不起作用

Question

知道为什么从 iOS 13 应用程序链接（通用链接）开始，这通过Apple-App-Site-Association停止工作来定义？

我在 ApplicationDelegate 和 SceneDelegate 中有 2 个实现。现在仅适用于 SceneDelegate 中的实现，并且仅当应用程序处于后台时，如果我杀死应用程序，则不会调用方法 continueUserActivity 。我添加了触觉反馈来跟踪这个方法调用，但它永远不会在 ActivityDelegate 或 SceneDelegate 中被调用。

// MARK: - Universal Links support
extension SceneDelegate {

    func scene(_ scene: UIScene, willContinueUserActivityWithType userActivityType: String) {
        print("[Scene] Will continue user activity: ", userActivityType)
        let generator = UINotificationFeedbackGenerator()
        generator.notificationOccurred(.success)

    }

    func scene(_ scene: UIScene, didFailToContinueUserActivityWithType userActivityType: String, error: Error) {
        print("[Scene] Did fail to continue user activity: ", userActivityType)
    }

    func scene(_ scene: UIScene, continue userActivity: NSUserActivity) {

        print("[Scene] Application continue user activity...")

        if userActivity.activityType == NSUserActivityTypeBrowsingWeb {
            if let url = userActivity.webpageURL {
                if !present(url: url) { UIApplication.shared.open(url, options: [:]) }
            }
        }
    }

和申请委托案例

// MARK: - Universal Links support
extension AppDelegate {

    func application(_ application: UIApplication, willContinueUserActivityWithType userActivityType: String) -> Bool {
        print("[App] Will continue user activity: ", userActivityType)
        let generator = UINotificationFeedbackGenerator()
        generator.notificationOccurred(.warning)
        return true
    }

    func application(_ application: UIApplication, didFailToContinueUserActivityWithType userActivityType: String, error: Error) {
        print("[App] Did fail to continue user activity: ", userActivityType)
    }

    func application(_ application: UIApplication, continue userActivity: NSUserActivity, restorationHandler: @escaping ([UIUserActivityRestoring]?) -> Void) -> Bool {

        print("[App] Application continue user activity...")

        if userActivity.activityType == NSUserActivityTypeBrowsingWeb {
            if let url = userActivity.webpageURL {
                if !present(url: url) { UIApplication.shared.open(url, options: [:]) }
            }
        }
        return true
    }

正在打开应用程序，但未调用方法，我无法导航到应用程序内的相应屏幕。

Answer 1

好的，我发现你必须做这样的事情

func scene(_ scene: UIScene, willConnectTo session: UISceneSession, options connectionOptions: UIScene.ConnectionOptions) {
   
    if let userActivity = connectionOptions.userActivities.first {
      self.scene(scene, continue: userActivity)
    }
  }