Ral*_*lph 27 scala immutability optional-values
我正在寻找这个问题的惯用解决方案.
我正在构建一个valScala(不可变)地图,并希望可选择添加一个或多个项目:
val aMap =
Map(key1 -> value1,
key2 -> value2,
(if (condition) (key3 -> value3) else ???))
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如何在不使用var?的情况下完成?什么应该取代????使用+运营商更好吗?
val aMap =
Map(key1 -> value1,
key2 -> value2) +
(if (condition) (key3 -> value3) else ???))
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一种可能的解决方案是
val aMap =
Map(key1 -> value1,
key2 -> value2,
(if (condition) (key3 -> value3) else (null, null))).filter {
case (k, v) => k != null && v != null
}
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这是最好的方法吗?
sbl*_*ndy 30
怎么样的东西
val optional = if(condition) Seq((key3 -> value3)) else Nil
val entities = Seq(key1 -> value1, key2 -> value2) ++ optional
val aMap = Map(entities:_*)
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Ero*_*ght 19
另一种可能性是利用可迭代的性质Option.
非空值o:
scala> val o = Some('z' -> 3)
scala> (Seq('x' -> 1, 'y' -> 2) ++ o).toMap
res1: scala.collection.immutable.Map[Char,Int] = Map(x -> 1, y -> 2, z -> 3)
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空值o:
scala> val o = None
scala> (Seq('x' -> 1, 'y' -> 2) ++ o).toMap
res2: scala.collection.immutable.Map[Char,Int] = Map(x -> 1, y -> 2)
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您可以直接添加到地图:
scala> val map = Map(1 -> 2, 3 -> 4)
scala> val some = Some(5 -> 6)
scala> val none = None
scala> val combinedMap = map ++ some ++ none
combinedMap: scala.collection.immutable.Map[Int,Int] = Map(1 -> 2, 3 -> 4, 5 -> 6)
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