sud*_*udo 49 java rest android authorization web-services
我使用Jersey Framework和Java在Netbean IDE中编写了一个REST Web服务.
对于用户需要提供用户名和密码的每个请求,我知道此身份验证不是最佳做法(使用curl命令,如:)curl -u username:password -X PUT http://localhsot:8080/user
.
现在我想从Android类调用REST Web服务.
我该怎么办?
我有一个使用DefaultHttpClient
和的Android类CredentialUsernameAndPassword
,但是当我在Eclipse中运行它时,有时会遇到运行时异常或SDK异常.
小智 19
这是一个示例restclient类
public class RestClient
{
public enum RequestMethod
{
GET,
POST
}
public int responseCode=0;
public String message;
public String response;
public void Execute(RequestMethod method,String url,ArrayList<NameValuePair> headers,ArrayList<NameValuePair> params) throws Exception
{
switch (method)
{
case GET:
{
// add parameters
String combinedParams = "";
if (params!=null)
{
combinedParams += "?";
for (NameValuePair p : params)
{
String paramString = p.getName() + "=" + URLEncoder.encode(p.getValue(),"UTF-8");
if (combinedParams.length() > 1)
combinedParams += "&" + paramString;
else
combinedParams += paramString;
}
}
HttpGet request = new HttpGet(url + combinedParams);
// add headers
if (headers!=null)
{
headers=addCommonHeaderField(headers);
for (NameValuePair h : headers)
request.addHeader(h.getName(), h.getValue());
}
executeRequest(request, url);
break;
}
case POST:
{
HttpPost request = new HttpPost(url);
// add headers
if (headers!=null)
{
headers=addCommonHeaderField(headers);
for (NameValuePair h : headers)
request.addHeader(h.getName(), h.getValue());
}
if (params!=null)
request.setEntity(new UrlEncodedFormEntity(params, HTTP.UTF_8));
executeRequest(request, url);
break;
}
}
}
private ArrayList<NameValuePair> addCommonHeaderField(ArrayList<NameValuePair> _header)
{
_header.add(new BasicNameValuePair("Content-Type","application/x-www-form-urlencoded"));
return _header;
}
private void executeRequest(HttpUriRequest request, String url)
{
HttpClient client = new DefaultHttpClient();
HttpResponse httpResponse;
try
{
httpResponse = client.execute(request);
responseCode = httpResponse.getStatusLine().getStatusCode();
message = httpResponse.getStatusLine().getReasonPhrase();
HttpEntity entity = httpResponse.getEntity();
if (entity != null)
{
InputStream instream = entity.getContent();
response = convertStreamToString(instream);
instream.close();
}
}
catch (Exception e)
{ }
}
private static String convertStreamToString(InputStream is)
{
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
String line = null;
try
{
while ((line = reader.readLine()) != null)
{
sb.append(line + "\n");
}
is.close();
}
catch (IOException e)
{ }
return sb.toString();
}
}
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Tia*_*hai 14
最近发现第三方库 - Square Retrofit可以很好地完成这项工作.
定义REST端点
public interface GitHubService {
@GET("/users/{user}/repos")
List<Repo> listRepos(@Path("user") String user,Callback<List<User>> cb);
}
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获得具体服务
RestAdapter restAdapter = new RestAdapter.Builder()
.setEndpoint("https://api.github.com")
.build();
GitHubService service = restAdapter.create(GitHubService.class);
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调用REST端点
List<Repo> repos = service.listRepos("octocat",new Callback<List<User>>() {
@Override
public void failure(final RetrofitError error) {
android.util.Log.i("example", "Error, body: " + error.getBody().toString());
}
@Override
public void success(List<User> users, Response response) {
// Do something with the List of Users object returned
// you may populate your adapter here
}
});
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该库为您处理json序列化和deserailization.您也可以自定义序列化和反序列化.
Gson gson = new GsonBuilder()
.setFieldNamingPolicy(FieldNamingPolicy.LOWER_CASE_WITH_UNDERSCORES)
.registerTypeAdapter(Date.class, new DateTypeAdapter())
.create();
RestAdapter restAdapter = new RestAdapter.Builder()
.setEndpoint("https://api.github.com")
.setConverter(new GsonConverter(gson))
.build();
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无论你做什么都停下来!:)
将RESTful客户端实现为SERVICE,并将密集型网络内容委托给与活动无关的组件:SERVICE.
观看这个富有洞察力的视频 http://www.youtube.com/watch?v=xHXn3Kg2IQE,其中Virgil Dobjanschi正在解释他对这一挑战的方法......
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