如何在android中插入%20代替空格

Question

我有一个xml URL文件,其中有空格我想用%20替换空格..怎么做？???

SAXParserFactory spf = SAXParserFactory.newInstance();
SAXParser sp = spf.newSAXParser();
XMLReader xr = sp.getXMLReader();

/** Send URL to parse XML Tags */
URL sourceUrl = new URL(
                "http://www.arteonline.mobi/iphone/output.php?gallery=MALBA%20-%20MUSEO%20DE%20ARTE%20LATINOAMERICANO%20DE%20BUENOS%20AIRES");

XMLHandlerartistspace myXMLHandler = new XMLHandlerartistspace();
xr.setContentHandler(myXMLHandler);
xr.parse(new InputSource(sourceUrl.openStream()));

Answer 1

试试这个:

String temp = http://www.arteonline.mobi/iphone/output.php?gallery=MALBA%20-%20MUSEO%20DE%20ARTE%20LATINOAMERICANO%20DE%20BUENOS%20AIRES

temp = temp.replaceAll(" ", "%20");
URL sourceUrl = new URL(temp);

Answer 2

构建URL时,应使用URLEncoder对参数进行编码.

StringBuilder query = new StringBuilder();
query.append("gallery=");
query.append(URLEncoder.encode(value, "UTF-8"));

如果您已经在String或java.net.URL中拥有整个URL,则可以获取查询部分并在URLEncoding每个参数值时重建.

Answer 3

只是sudocode响应的一个补充:

使用android.net.Uri.encode而不是URLEncoder.encode来避免"空间转换成+"问题.然后你摆脱了String.replaceAll(),它更优雅:)

StringBuilder query = new StringBuilder();
query.append("gallery=");
query.append(android.net.Uri.encode(value, "UTF-8"));