对象问题中的Jquery对象

Question

我有这个对象:

question =  {
  "name":"Foo",
  "number":"123", 
  "options":{"1":"1 - 20","2":"21 - 30","etc":"etc"} 
}

现在,如果我这样做:

$(question.options).each(function(k,v){
    console.log(k,v)
    // This should spit out: 1,a; 2,b; etc,etc ....
});

但它将选项作为单个对象吐出:0对象{1 ="1 - 20",2 ="21 - 30",更多...}

Answer 1

您应该使用$.each(object, fn)迭代一个普通的JS对象.jQuery没有正式支持将普通对象传递给它的构造函数.

$.each(question.options, function( key, value ){
    console.log( key, value );
});