gpi*_*ler 7 core-data swift cloudkit ios13
我遇到以下场景,我从 JSON 文件解析对象并将它们存储到我的核心数据存储中。现在我正在使用NSPersistentCloudKitContainer,当我在不同的设备上运行该应用程序时,它还会解析 JSON 文件并将对象添加到核心数据中。这会导致重复的对象。
现在我想知道是否有:
也许现在回答已经太晚了,但我最近正在研究同样的问题。经过几周的研究,我想在这里留下我所学到的东西,希望能帮助有同样问题的人。
\n\n\n如果我可以检查实体是否已远程存在,这是一种简单的方法吗?
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\n\n还有其他方法可以避免对象在 CloudKit 中保存两次吗?
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是的,我们可以检查该实体是否已存在于 iCloud 上,但这并不是决定是否解析 JSON 文件并将其保存到 CoreData permanentStore 的最佳方法。应用程序可能未连接到 Apple ID / iCloud,或者存在某些网络问题,导致无法可靠地检查该实体是否远程存在。
\n当前的解决方案是我们自己删除重复数据,方法是向从 JSON 文件添加的每个数据对象添加一个 UUID 字段,并删除具有相同 UUID 的对象。\n大多数时候我还会添加一个 lastUpdate 字段,这样我们就可以保留最新的数据对象。
\n\n\n从远程获取数据完成时收到通知吗?
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我们可以添加 NSPersistentStoreRemoteChange 的观察者,并在远程存储发生更改时收到通知。
\nApple 提供了一个使用 CoreData 和 CloudKit 的演示项目,并很好地解释了重复数据删除。
\n将本地存储同步到云\n https://developer.apple.com/documentation/coredata/synchronizing_a_local_store_to_the_cloud
\nWWDC2019 会议 202:将 CoreData 与 CloudKit 结合使用\n https://developer.apple.com/videos/play/wwdc2019/202
\n整个想法是监听远程存储中的更改,跟踪更改历史记录,并在有任何新数据传入时对数据进行重复数据删除。(当然我们需要一些字段来确定数据是否重复)。持久存储提供了历史记录跟踪功能,我们可以在这些事务合并到本地存储时获取这些事务,并运行我们的重复数据删除过程。假设我们将在应用程序启动时解析 JSON 并导入标签:
\n// Use a custom queue to ensure only one process of history handling at the same time\nprivate lazy var historyQueue: OperationQueue = {\n let queue = OperationQueue()\n queue.maxConcurrentOperationCount = 1\n return queue\n}()\n\nlazy var persistentContainer: NSPersistentContainer = {\n let container = NSPersistentCloudKitContainer(name: "CoreDataCloudKitDemo")\n\n ...\n // set the persistentStoreDescription to track history and generate notificaiton (NSPersistentHistoryTrackingKey, NSPersistentStoreRemoteChangeNotificationPostOptionKey)\n // load the persistentStores\n // set the mergePolicy of the viewContext\n ...\n\n // Observe Core Data remote change notifications.\n NotificationCenter.default.addObserver(\n self, selector: #selector(type(of: self).storeRemoteChange(_:)),\n name: .NSPersistentStoreRemoteChange, object: container.persistentStoreCoordinator)\n\n return container\n}()\n\n@objc func storeRemoteChange(_ notification: Notification) {\n // Process persistent history to merge changes from other coordinators.\n historyQueue.addOperation {\n self.processPersistentHistory()\n }\n}\n\n// To fetch change since last update, deduplicate if any new insert data, and save the updated token\nprivate func processPersistentHistory() {\n // run in a background context and not blocking the view context.\n // when background context is saved, it will merge to the view context based on the merge policy\n let taskContext = persistentContainer.newBackgroundContext()\n taskContext.performAndWait {\n // Fetch history received from outside the app since the last token\n let historyFetchRequest = NSPersistentHistoryTransaction.fetchRequest!\n let request = NSPersistentHistoryChangeRequest.fetchHistory(after: lastHistoryToken)\n request.fetchRequest = historyFetchRequest\n\n let result = (try? taskContext.execute(request)) as? NSPersistentHistoryResult\n guard let transactions = result?.result as? [NSPersistentHistoryTransaction],\n !transactions.isEmpty\n else { return }\n\n // Tags from remote store\n var newTagObjectIDs = [NSManagedObjectID]()\n let tagEntityName = Tag.entity().name\n\n // Append those .insert change in the trasactions that we want to deduplicate\n for transaction in transactions where transaction.changes != nil {\n for change in transaction.changes!\n where change.changedObjectID.entity.name == tagEntityName && change.changeType == .insert {\n newTagObjectIDs.append(change.changedObjectID)\n }\n }\n\n if !newTagObjectIDs.isEmpty {\n deduplicateAndWait(tagObjectIDs: newTagObjectIDs)\n }\n \n // Update the history token using the last transaction.\n lastHistoryToken = transactions.last!.token\n }\n}\nRun Code Online (Sandbox Code Playgroud)\n在这里,我们保存添加的标签的 ObjectID,以便我们可以在任何其他对象上下文上对它们进行重复数据删除,
\nprivate func deduplicateAndWait(tagObjectIDs: [NSManagedObjectID]) {\n let taskContext = persistentContainer.backgroundContext()\n \n // Use performAndWait because each step relies on the sequence. Since historyQueue runs in the background, waiting won\xe2\x80\x99t block the main queue.\n taskContext.performAndWait {\n tagObjectIDs.forEach { tagObjectID in\n self.deduplicate(tagObjectID: tagObjectID, performingContext: taskContext)\n }\n // Save the background context to trigger a notification and merge the result into the viewContext.\n taskContext.save(with: .deduplicate)\n }\n}\n\nprivate func deduplicate(tagObjectID: NSManagedObjectID, performingContext: NSManagedObjectContext) {\n // Get tag by the objectID\n guard let tag = performingContext.object(with: tagObjectID) as? Tag,\n let tagUUID = tag.uuid else {\n fatalError("###\\(#function): Failed to retrieve a valid tag with ID: \\(tagObjectID)")\n }\n\n // Fetch all tags with the same uuid\n let fetchRequest: NSFetchRequest<Tag> = Tag.fetchRequest()\n // Sort by lastUpdate, keep the latest Tag\n fetchRequest.sortDescriptors = [NSSortDescriptor(key: "lastUpdate", ascending: false)]\n\n fetchRequest.predicate = NSPredicate(format: "uuid == %@", tagUUID)\n \n // Return if there are no duplicates.\n guard var duplicatedTags = try? performingContext.fetch(fetchRequest), duplicatedTags.count > 1 else {\n return\n }\n // Pick the first tag as the winner.\n guard let winner = duplicatedTags.first else {\n fatalError("###\\(#function): Failed to retrieve the first duplicated tag")\n }\n duplicatedTags.removeFirst()\n remove(duplicatedTags: duplicatedTags, winner: winner, performingContext: performingContext)\n}\nRun Code Online (Sandbox Code Playgroud)\n最困难的部分(在我看来)是处理被删除的重复对象的关系,假设我们的 Tag 对象与 Category 对象有一对多的关系(每个 Tag 可能有多个 Category)
\nprivate func remove(duplicatedTags: [Tag], winner: Tag, performingContext: NSManagedObjectContext) {\n duplicatedTags.forEach { tag in\n // delete the tag AFTER we handle the relationship\n // and be careful that the delete rule will also activate\n defer { performingContext.delete(tag) }\n \n if let categorys = tag.categorys as? Set<Category> {\n for category in categorys {\n // re-map those category to the winner Tag, or it will become nil when the duplicated Tag got delete\n category.ofTag = winner\n }\n }\n }\n}\nRun Code Online (Sandbox Code Playgroud)\n一件有趣的事情是,如果 Category 对象也是从远程存储中添加的,那么当我们处理关系时它们可能还不存在,但那是另一回事了。
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