从画布中绘制的弧获取坐标

Question

我Canvas.drawArc()在Android Studio 中工作，我找到了正确绘制我需要的弧的方法，但我想知道Point()实际创建弧的坐标Arc（不是边缘，而是中间的一些）。我已经拥有的代码是：

画圆弧（作品）

// Set the arc of movement of the encoder
public void setArc(Canvas canvas, Point startPoint, Point endPoint){
    Point centerArc = new Point((int) centerX, (int) centerY);
    Point leftEdge = new Point(startPoint.x, startPoint.y);
    Point rightEdge = new Point(endPoint.x, endPoint.y);

    int radiusArc = (int) Math.sqrt((leftEdge.x - centerArc.x)*(leftEdge.x - centerArc.x) + (leftEdge.y - centerArc.y)*(leftEdge.y - centerArc.y));

    int startAngle = (int) (190/Math.PI*atan2(leftEdge.y-centerArc.y, leftEdge.x-centerArc.x));
    int endAngle = (int) (210/Math.PI*atan2(rightEdge.y-centerArc.y, rightEdge.x-centerArc.y));

    RectF rect = new RectF(centerX - radiusArc, centerY - radiusArc, centerX + radiusArc, centerY + radiusArc);
    canvas.drawArc(rect, startAngle, endAngle, true, mRectPaint);
}

问题是，由于Canvas.drawArc()是一种void方法，我不确定如何获得这些坐标。

有什么建议吗？确实，我什至对绘制Arc. 我只是在寻找一种方法来实际获得这些坐标。

也许有一种方法可以在 java 中的 3 个点内创建一条曲线，我可以获得坐标。我不介意使用这种方法。

第一种方法

我已经尝试遵循这个答案，但我得到的值不是正确的

//  Calculate the coordinates of 100 points of the arc
    Point[] coordinatesArc = new Point[100];
    coordinatesArc[0] = startPoint;
    Point coordinate = new Point();
    int xCoordinate;
    int yCoordinate;
    for (int i = 1; i<=98; i++){
        xCoordinate = startPoint.x + radiusArc*(int)Math.sin(i);
        yCoordinate = startPoint.y - radiusArc*(1-(int)Math.cos(i));
        coordinate.set(xCoordinate, yCoordinate);
        coordinatesArc[i]=coordinate;
    }
    coordinatesArc[99]= endPoint;
    Log.d(TAG, "Values: x = " + String.valueOf(coordinatesArc[97].x) + " y = " + String.valueOf(coordinatesArc[97].y) );

第二种方法

我还检查了 Android 的Path，但我不知道是否可以使用它。似乎有几种方法 (arcTo和addArc) 可以提供帮助，但我不知道如何将它附加到画布上，所以我想不可能将它们组合起来。

第三种方法

在找到另一个先前的答案后，我试图实现它，但坐标又是错误的（甚至不接近我的endPoint）。

Point centerArc = new Point((int) centerX, (int) centerY);
    Point leftEdge = new Point(startPoint.x, startPoint.y);
    int radiusArc = (int) Math.sqrt((leftEdge.x - centerArc.x)*(leftEdge.x - centerArc.x) + (leftEdge.y - centerArc.y)*(leftEdge.y - centerArc.y));
    int startAngle = (int) (190/Math.PI*atan2(leftEdge.y-centerArc.y, leftEdge.x-centerArc.x));

    Point[] coordinatesArc = new Point[100];
    Point auxPoint = new Point();
    coordinatesArc[0] = startPoint;
    for(int i = 1; i<=98;i++){
        auxPoint.x = (int) (centerX + radiusArc * Math.cos(startAngle + i));
        auxPoint.y = (int) (centerY + radiusArc * Math.sin(startAngle + i));
        coordinatesArc[i]= auxPoint;
    }
    coordinatesArc[99]= endPoint;
    Log.d(TAG, "COORDINATES ARC: x =  " + coordinatesArc[98].x  + " & y = " + coordinatesArc[98].y);

Answer 1

使用Path和PathMeasure尝试以下操作。

该示例类利用了自定义视图。绘制弧线，然后沿着弧线放置二十个小圆圈。您可以通过除以路径长度将路径划分为任意多个点。数组arcPoints将包含沿路径选择的点。

如果您不想绘制圆弧或点，只需删除执行实际画布绘制的代码即可。仍将创建路径并捕获路径沿线的点。

MyView.java

 final Path mPath = new Path();

    int startAngle = (int) (190/Math.PI*atan2(startPoint.y-centerY, startPoint.x-centerX));
    int sweepAngle = (int) (210/Math.PI*atan2(endPoint.y-centerY, endPoint.x-centerX));
    int radiusArc = (int) Math.sqrt((startPoint.x - centerX)*(startPoint.x - centerX) + (startPoint.y - centerY)*(startPoint.y - centerY));

    final RectF oval = new RectF(centerX - radiusArc, centerY - radiusArc, centerX + radiusArc, centerY + radiusArc);

    mPath.addArc(oval, startAngle, sweepAngle);

    PathMeasure pm = new PathMeasure(mPath, false);
    float[] xyCoordinate = {startPoint.x, startPoint.y};
    float pathLength = pm.getLength();

    // Capture the points along the arc.
    PointF[] arcPoints = new PointF[20];
    for (int i = 0; i < 20; i++) {
        pm.getPosTan(pathLength * i / 19, xyCoordinate, null);
        arcPoints[i] = new PointF(xyCoordinate[0], xyCoordinate[1]);
    }

    Log.d(TAG, Arrays.toString(arcPoints));
    // Do drawing just to show the code works. Delete if drawing is not needed.
    canvas.drawPath(mPath, mRectPaint);
    for (int i = 0; i < 20; i++) {
        Log.d(TAG, String.format("Point #%d = (%.0f,%.0f)", i + 1, xyCoordinate[0], xyCoordinate[1]));
        canvas.drawCircle(arcPoints[i].x, arcPoints[i].y, 10, mTracerPaint); // Radius of the coordinate circle drawn.
    }