Nav*_*han 64 sql database oracle ora-00904
我尝试使用Oracle数据库编写以下内部联接查询:
SELECT Employee.EMPLID as EmpID,
Employee.FIRST_NAME AS Name,
Team.DEPARTMENT_CODE AS TeamID,
Team.Department_Name AS teamname
FROM PS_TBL_EMPLOYEE_DETAILS Employee
INNER JOIN PS_TBL_DEPARTMENT_DETAILS Team
ON Team.DEPARTMENT_CODE = Employee.DEPTID
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这给出了以下错误:
INNER JOIN PS_TBL_DEPARTMENT_DETAILS Team ON Team.DEPARTMENT_CODE = Employee.DEPTID
*
ERROR at line 4:
ORA-00904: "TEAM"."DEPARTMENT_CODE": invalid identifier
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一个表的DDL是:
CREATE TABLE "HRMS"."PS_TBL_DEPARTMENT_DETAILS"
(
"Company Code" VARCHAR2(255),
"Company Name" VARCHAR2(255),
"Sector_Code" VARCHAR2(255),
"Sector_Name" VARCHAR2(255),
"Business_Unit_Code" VARCHAR2(255),
"Business_Unit_Name" VARCHAR2(255),
"Department_Code" VARCHAR2(255),
"Department_Name" VARCHAR2(255),
"HR_ORG_ID" VARCHAR2(255),
"HR_ORG_Name" VARCHAR2(255),
"Cost_Center_Number" VARCHAR2(255),
" " VARCHAR2(255)
)
SEGMENT CREATION IMMEDIATE PCTFREE 10 PCTUSED 40 INITRANS 1 MAXTRANS 255 NOCOMPRESS
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APC*_*APC 105
你的问题是那些有害的双引号.
SQL> CREATE TABLE "APC"."PS_TBL_DEPARTMENT_DETAILS"
2 (
3 "Company Code" VARCHAR2(255),
4 "Company Name" VARCHAR2(255),
5 "Sector_Code" VARCHAR2(255),
6 "Sector_Name" VARCHAR2(255),
7 "Business_Unit_Code" VARCHAR2(255),
8 "Business_Unit_Name" VARCHAR2(255),
9 "Department_Code" VARCHAR2(255),
10 "Department_Name" VARCHAR2(255),
11 "HR_ORG_ID" VARCHAR2(255),
12 "HR_ORG_Name" VARCHAR2(255),
13 "Cost_Center_Number" VARCHAR2(255),
14 " " VARCHAR2(255)
15 )
16 /
Table created.
SQL>
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Oracle SQL允许我们忽略数据库对象名称的情况,前提是我们使用大写的名称创建它们,或者不使用双引号.如果我们在脚本中使用大小写或小写并用双引号包装标识符,那么每当我们引用对象或其属性时,我们都会被判使用双引号和精确的大小写:
SQL> select count(*) from PS_TBL_DEPARTMENT_DETAILS
2 where Department_Code = 'BAH'
3 /
where Department_Code = 'BAH'
*
ERROR at line 2:
ORA-00904: "DEPARTMENT_CODE": invalid identifier
SQL> select count(*) from PS_TBL_DEPARTMENT_DETAILS
2 where "Department_Code" = 'BAH'
3 /
COUNT(*)
----------
0
SQL>
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TL;博士
不要在DDL脚本中使用双引号
(我知道大多数第三方代码生成器都可以,但是它们足够严格,可以将所有对象名称放在UPPER CASE中.)
仅供参考,在这种情况下,发现原因是 DDL 中用于表创建的列名混合大小写。
但是,如果您混合使用“旧样式”和 ANSI 连接,即使 DDL 使用大写表名正确完成,您也可能会收到相同的错误消息。这发生在我身上,谷歌将我发送到这个 stackoverflow 页面,所以我想我会在这里分享。
--NO PROBLEM: ANSI syntax
SELECT A.EMPLID, B.FIRST_NAME, C.LAST_NAME
FROM PS_PERSON A
INNER JOIN PS_NAME_PWD_VW B ON B.EMPLID = A.EMPLID
INNER JOIN PS_HCR_PERSON_NM_I C ON C.EMPLID = A.EMPLID
WHERE
LENGTH(A.EMPLID) = 9
AND LENGTH(B.LAST_NAME) > 5
AND LENGTH(C.LAST_NAME) > 5
ORDER BY 1, 2, 3
/
--NO PROBLEM: OLD STYLE/deprecated/traditional oracle proprietary join syntax
SELECT A.EMPLID, B.FIRST_NAME, C.LAST_NAME
FROM PS_PERSON A
, PS_NAME_PWD_VW B
, PS_HCR_PERSON_NM_I C
WHERE
B.EMPLID = A.EMPLID
and C.EMPLID = A.EMPLID
and LENGTH(A.EMPLID) = 9
AND LENGTH(B.LAST_NAME) > 5
AND LENGTH(C.LAST_NAME) > 5
ORDER BY 1, 2, 3
/
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上面两条 SQL 语句是等价的,不会产生错误。
当您尝试混合它们时,您可能会很幸运,或者您可能会遇到 Oracle 出现 ORA-00904 错误。
--LUCKY: mixed syntax (ANSI joins appear before OLD STYLE)
SELECT A.EMPLID, B.FIRST_NAME, C.LAST_NAME
FROM
PS_PERSON A
inner join PS_HCR_PERSON_NM_I C on C.EMPLID = A.EMPLID
, PS_NAME_PWD_VW B
WHERE
B.EMPLID = A.EMPLID
and LENGTH(A.EMPLID) = 9
AND LENGTH(B.FIRST_NAME) > 5
AND LENGTH(C.LAST_NAME) > 5
/
--PROBLEM: mixed syntax (OLD STYLE joins appear before ANSI)
--http://sqlfascination.com/2013/08/17/oracle-ansi-vs-old-style-joins/
SELECT A.EMPLID, B.FIRST_NAME, C.LAST_NAME
FROM
PS_PERSON A
, PS_NAME_PWD_VW B
inner join PS_HCR_PERSON_NM_I C on C.EMPLID = A.EMPLID
WHERE
B.EMPLID = A.EMPLID
and LENGTH(A.EMPLID) = 9
AND LENGTH(B.FIRST_NAME) > 5
AND LENGTH(C.LAST_NAME) > 5
/
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以及根本没有真正描述问题的无用错误消息:
>[Error] Script lines: 1-12 -------------------------
ORA-00904: "A"."EMPLID": invalid identifier Script line 6, statement line 6,
column 51
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我能够在以下博客文章中找到一些关于此的研究:
就我而言,我试图手动从旧样式转换为 ANSI 样式连接,并且以增量方式进行,一次一个表。这似乎是一个坏主意。相反,最好一次转换所有表,或者在原始查询中注释掉一个表及其 where 条件,以便与您正在编写的新 ANSI 查询进行比较。