在 linux 文件中逐行比较

Question

我有一个这样的文件（test1.txt）：

100 100
200 200
300 HR
400 IT
500 500
600 600

我想要这样的输出：

100 100 0
200 200 0
300 HR  1
400 IT  1
500 500 0
600 600 0

我已经尝试运行此命令：

#!/bin/bash

awk1=`awk '{print $1}' test1.txt`
awk2=`awk '{print $2}' test1.txt`

if [ "$awk1" = "$awk2" ]; then
        echo "0"
else
        echo "1"
fi

但结果并不像我预期的那样。

Answer 1

你能不能试试以下。

awk '{$(NF+1)=$1==$2?0:1} 1' Input_file

或者让输出 TAB 分隔尝试：

awk 'BEGIN{OFS="\t"} {$(NF+1)=$1==$2?0:1} 1' Input_file

说明：为上述代码添加详细说明。

awk '                   ##Starting awk program from here.
{
  $(NF+1)=$1==$2?0:1    ##Creating a new NF+1 field which will be newer last field and its value will be decided as per condition:
}                       ##If $1 and $2 are equal then set 0 or set 1 its value.
1                       ##1 will print the complete line value here(including new last field value).
' Input_file            ##Mentioning Input_file name here.