Nic*_*las 1 java spring spring-mvc spring-security
我无法使用正确的详细信息登录,因为程序不断指出编码的密码看起来不像 bcrypt。有谁知道如何解决这个问题?我正在使用 JDBC 身份验证。
我也有正确的数据库表,有足够的空间用于编码密码。我不确定哪里出了问题。
JSP 表单: <form:form method="post" modelAttribute="user" action="${pageContext.request.contextPath}/processLogin">
<div class="form-group">
<div class="form-label-group">
<label for="inputUser">Username: </label> <input name="username"
type="text" path="username" id="inputUser" class="form-control"
placeholder="Username" required="required" autofocus="autofocus">
</div>
</div>
<div class="form-group">
<div class="form-label-group">
<label for="inputPassword">Password: </label>
<input name="username" type="password" path="password"
id="inputPassword" class="form-control" placeholder="Password"
required="required">
</div>
</div>
<div class="form-group">
<div class="checkbox">
<label> <input type="checkbox" value="remember-me">
Remember Password
</label>
</div>
</div>
<input type="submit" value="Login"/>
</form:form>
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安全配置:
@Autowired
private DataSource securityDataSource;
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.jdbcAuthentication().dataSource(securityDataSource).passwordEncoder(passwordEncoder());
}
@Override
protected void configure(HttpSecurity http) throws Exception {
http.authorizeRequests().antMatchers("/management/**").authenticated().and().formLogin().loginPage("/login")
.loginProcessingUrl("/processLogin").defaultSuccessUrl("/management/dashboard").permitAll();
http.exceptionHandling().accessDeniedPage("/access-denied");
}
@Bean
@Autowired
public BCryptPasswordEncoder passwordEncoder() {
return new BCryptPasswordEncoder();
}
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登录控制器
@Controller
public class LoginController {
@Autowired
private UserServiceImpl userService;
@GetMapping("/login")
public String showLoginForm(Model model) {
User user = new User();
model.addAttribute("user", user);
return "login";
}
@PostMapping("/processLogin")
public String processLogin(@ModelAttribute("user") User user, Model model) {
if (userService.findUser(user.getUsername(), user.getPassword()) != null) {
return "/management/dashboard";
} else {
return "/access-denied";
}
}
}
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小智 7
我通过使用BcryptPasswordEncoder以下方法解决了我的问题
@Override
public UserDetails loadUserByUsername(String userName) throws UsernameNotFoundException {
User user = userRepository.findByuserName(userName);
if (user == null) {
throw new UsernameNotFoundException("userName" + userName + "Not found in the database");
}
return new org.springframework.security.core.userdetails.User(user.getName(), new BCryptPasswordEncoder().encode(user.getPassword()), getGrantedAuth(user));
}
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